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Sketching the Gradient notes

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Sketching the gradient
02 October 2020 13:18
Example 1:
gradient
decreasing.
(is negitan
+ve
Example 2:
tue
1
1
(-2,0)
-3,0)
(gradient
is ne

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Sketching the gradient
02 October 2020 13:18
Example 1:
gradient
decreasing.
(is negitan
+ve
Example 2:
tue
1
1
(-2,0)
-3,0)
(gradient
is ne

Sign up

Sign up to get unlimited access to thousands of study materials. It's free!

Access to all documents

Join milions of students

Improve your grades

By signing up you accept Terms of Service and Privacy Policy

Sketching the gradient 02 October 2020 13:18 Example 1: gradient decreasing. (is negitan +ve Example 2: tue 1 1 (-2,0) -3,0) (gradient is negitave) dy (gradiat) d₂ (-3,4) (-3,0) -ve (3,5) dx (1,-3) tve (₁,0) at sp dy = 0 dx (3,0) tve Differentiation 2 Page 1 This is a cubic graph (x³ turm) after x = 3, gradient. is decreasing (negitave) 1 04 dx = 0 dx -ve (61,-3) PTO 1 (3,0) (16.0) -v( Question: Sketch the derived graph of f(x) = (x - 2)² x x +vc tve Sketch the derived graph (graph of what happens to the gradient). AI X • at Sp's dy 0 roots of the dx gradient curve • look at the gradient either side. Of the JPJ function decreasing =) gradient -ve => below x Sketch the derived graph. axis 'function increasing => gradient tve =) above x axis. positive above x axis. negitave below x axis f(x) -ve (2,0) TV V tvc 1(210) -vc f'(x) ant 1 x f(x)=(x-2)² just y=x² (normal symetrical graph) but moved right 2. quadratic - linear !

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Sketching the Gradient notes

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Maths

 

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Revision note

Sketching the gradient
02 October 2020 13:18
Example 1:
gradient
decreasing.
(is negitan
+ve
Example 2:
tue
1
1
(-2,0)
-3,0)
(gradient
is ne
Sketching the gradient
02 October 2020 13:18
Example 1:
gradient
decreasing.
(is negitan
+ve
Example 2:
tue
1
1
(-2,0)
-3,0)
(gradient
is ne

notes for higher maths on how to sketch the gradient

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Sketching the gradient 02 October 2020 13:18 Example 1: gradient decreasing. (is negitan +ve Example 2: tue 1 1 (-2,0) -3,0) (gradient is negitave) dy (gradiat) d₂ (-3,4) (-3,0) -ve (3,5) dx (1,-3) tve (₁,0) at sp dy = 0 dx (3,0) tve Differentiation 2 Page 1 This is a cubic graph (x³ turm) after x = 3, gradient. is decreasing (negitave) 1 04 dx = 0 dx -ve (61,-3) PTO 1 (3,0) (16.0) -v( Question: Sketch the derived graph of f(x) = (x - 2)² x x +vc tve Sketch the derived graph (graph of what happens to the gradient). AI X • at Sp's dy 0 roots of the dx gradient curve • look at the gradient either side. Of the JPJ function decreasing =) gradient -ve => below x Sketch the derived graph. axis 'function increasing => gradient tve =) above x axis. positive above x axis. negitave below x axis f(x) -ve (2,0) TV V tvc 1(210) -vc f'(x) ant 1 x f(x)=(x-2)² just y=x² (normal symetrical graph) but moved right 2. quadratic - linear !

Sketching the gradient 02 October 2020 13:18 Example 1: gradient decreasing. (is negitan +ve Example 2: tue 1 1 (-2,0) -3,0) (gradient is negitave) dy (gradiat) d₂ (-3,4) (-3,0) -ve (3,5) dx (1,-3) tve (₁,0) at sp dy = 0 dx (3,0) tve Differentiation 2 Page 1 This is a cubic graph (x³ turm) after x = 3, gradient. is decreasing (negitave) 1 04 dx = 0 dx -ve (61,-3) PTO 1 (3,0) (16.0) -v( Question: Sketch the derived graph of f(x) = (x - 2)² x x +vc tve Sketch the derived graph (graph of what happens to the gradient). AI X • at Sp's dy 0 roots of the dx gradient curve • look at the gradient either side. Of the JPJ function decreasing =) gradient -ve => below x Sketch the derived graph. axis 'function increasing => gradient tve =) above x axis. positive above x axis. negitave below x axis f(x) -ve (2,0) TV V tvc 1(210) -vc f'(x) ant 1 x f(x)=(x-2)² just y=x² (normal symetrical graph) but moved right 2. quadratic - linear !

Can't find what you're looking for? Explore other subjects.

Knowunity is the # 1 ranked education app in five European countries

Knowunity is the # 1 ranked education app in five European countries

Knowunity was a featured story by Apple and has consistently topped the app store charts within the education category in Germany, Italy, Poland, Switzerland and United Kingdom. Join Knowunity today and help millions of students around the world.

Ranked #1 Education App

Download in

Google Play

Download in

App Store

Still not sure? Look at what your fellow peers are saying...

iOS User

I love this app so much [...] I recommend Knowunity to everyone!!! I went from a C to an A with it :D

Stefan S, iOS User

The application is very simple and well designed. So far I have found what I was looking for :D

SuSSan, iOS User

Love this App ❤️, I use it basically all the time whenever I'm studying