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The Fundamental Theorem of Calculus and Accumulation

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6.4 the fundamental thoum of Cole & tummulation
interval w/ unknown stop point gives us
[a, x], where is a constant & xis
an unknown vanable

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6.4 the fundamental thoum of Cole & tummulation interval w/ unknown stop point gives us [a, x], where is a constant & xis an unknown vanable. this as a function looks like FGX) = Sr. Frede 1. let F(x) = So f(t) dt. Find values of table on interval 0²x²5 2) complete tables the disa X 2 3 5 5 5.5 S 4 E(X) 0 2.5 4 a001.5 Sof(t)dt = 0 Sof(t) sof(t) Sof Saf Sof -1- this is called an acrymulanya fuachan Fundamental theemm of raichtes if a is constant's f is a continuous cunction, then d &/ S₁ f(t) dt = $(30 F(x)=√x Stdt 5(x)·() - 5(-x)•(-D) = 5X-5x =JD1 svariations of ftc if a is constant, & is a continuous $19(x) derivatives & integrals are inverses of each other, they cancel each other out, just like multiplication & division in example 1, the graph of f is the derivative of F(x). So F(X) is considered the antiderivative of f(x) Find Flex) F(x)=√₁² (3+² +4 t) dt F(X)= 3x² + UX 2. F(x) = √7/² sin(e) de F'(x) = sin(x³). 3x² 3x² sin(x³) ((t) 2 3 4 3. F(X) = Sy het dt F'(x) = n(4x).4 - 4 h(4x)] 5. F(x)=√x (t²-t) dt [(3x)²-(3x)]-3-[(2x)²-(2x)]·2=19x²-5x function, s gsh are differentiable then f(t)dt = f(g(x)) · g'(x). & S(x) f(t) dt = f(g(x)) · g'(x) = f(h(x)) - h'(x).

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The Fundamental Theorem of Calculus and Accumulation

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Calculus AB

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Isabel Banayad

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6.4 the fundamental thoum of Cole & tummulation
interval w/ unknown stop point gives us
[a, x], where is a constant & xis
an unknown vanable

An introduction to the fundamental theorem of calculus and antiderivatives.

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6.4 the fundamental thoum of Cole & tummulation interval w/ unknown stop point gives us [a, x], where is a constant & xis an unknown vanable. this as a function looks like FGX) = Sr. Frede 1. let F(x) = So f(t) dt. Find values of table on interval 0²x²5 2) complete tables the disa X 2 3 5 5 5.5 S 4 E(X) 0 2.5 4 a001.5 Sof(t)dt = 0 Sof(t) sof(t) Sof Saf Sof -1- this is called an acrymulanya fuachan Fundamental theemm of raichtes if a is constant's f is a continuous cunction, then d &/ S₁ f(t) dt = $(30 F(x)=√x Stdt 5(x)·() - 5(-x)•(-D) = 5X-5x =JD1 svariations of ftc if a is constant, & is a continuous $19(x) derivatives & integrals are inverses of each other, they cancel each other out, just like multiplication & division in example 1, the graph of f is the derivative of F(x). So F(X) is considered the antiderivative of f(x) Find Flex) F(x)=√₁² (3+² +4 t) dt F(X)= 3x² + UX 2. F(x) = √7/² sin(e) de F'(x) = sin(x³). 3x² 3x² sin(x³) ((t) 2 3 4 3. F(X) = Sy het dt F'(x) = n(4x).4 - 4 h(4x)] 5. F(x)=√x (t²-t) dt [(3x)²-(3x)]-3-[(2x)²-(2x)]·2=19x²-5x function, s gsh are differentiable then f(t)dt = f(g(x)) · g'(x). & S(x) f(t) dt = f(g(x)) · g'(x) = f(h(x)) - h'(x).

6.4 the fundamental thoum of Cole & tummulation interval w/ unknown stop point gives us [a, x], where is a constant & xis an unknown vanable. this as a function looks like FGX) = Sr. Frede 1. let F(x) = So f(t) dt. Find values of table on interval 0²x²5 2) complete tables the disa X 2 3 5 5 5.5 S 4 E(X) 0 2.5 4 a001.5 Sof(t)dt = 0 Sof(t) sof(t) Sof Saf Sof -1- this is called an acrymulanya fuachan Fundamental theemm of raichtes if a is constant's f is a continuous cunction, then d &/ S₁ f(t) dt = $(30 F(x)=√x Stdt 5(x)·() - 5(-x)•(-D) = 5X-5x =JD1 svariations of ftc if a is constant, & is a continuous $19(x) derivatives & integrals are inverses of each other, they cancel each other out, just like multiplication & division in example 1, the graph of f is the derivative of F(x). So F(X) is considered the antiderivative of f(x) Find Flex) F(x)=√₁² (3+² +4 t) dt F(X)= 3x² + UX 2. F(x) = √7/² sin(e) de F'(x) = sin(x³). 3x² 3x² sin(x³) ((t) 2 3 4 3. F(X) = Sy het dt F'(x) = n(4x).4 - 4 h(4x)] 5. F(x)=√x (t²-t) dt [(3x)²-(3x)]-3-[(2x)²-(2x)]·2=19x²-5x function, s gsh are differentiable then f(t)dt = f(g(x)) · g'(x). & S(x) f(t) dt = f(g(x)) · g'(x) = f(h(x)) - h'(x).

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Knowunity is the # 1 ranked education app in five European countries

Knowunity is the # 1 ranked education app in five European countries

Knowunity was a featured story by Apple and has consistently topped the app store charts within the education category in Germany, Italy, Poland, Switzerland and United Kingdom. Join Knowunity today and help millions of students around the world.

Ranked #1 Education App

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Google Play

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App Store

Still not sure? Look at what your fellow peers are saying...

iOS User

I love this app so much [...] I recommend Knowunity to everyone!!! I went from a C to an A with it :D

Stefan S, iOS User

The application is very simple and well designed. So far I have found what I was looking for :D

SuSSan, iOS User

Love this App ❤️, I use it basically all the time whenever I'm studying