Download in
Google Play
1
Share
Save
Sign up
Access to all documents
Join milions of students
Improve your grades
By signing up you accept Terms of Service and Privacy Policy
6.4 the fundamental thoum of Cole & tummulation interval w/ unknown stop point gives us [a, x], where is a constant & xis an unknown vanable. this as a function looks like FGX) = Sr. Frede 1. let F(x) = So f(t) dt. Find values of table on interval 0²x²5 2) complete tables the disa X 2 3 5 5 5.5 S 4 E(X) 0 2.5 4 a001.5 Sof(t)dt = 0 Sof(t) sof(t) Sof Saf Sof -1- this is called an acrymulanya fuachan Fundamental theemm of raichtes if a is constant's f is a continuous cunction, then d &/ S₁ f(t) dt = $(30 F(x)=√x Stdt 5(x)·() - 5(-x)•(-D) = 5X-5x =JD1 svariations of ftc if a is constant, & is a continuous $19(x) derivatives & integrals are inverses of each other, they cancel each other out, just like multiplication & division in example 1, the graph of f is the derivative of F(x). So F(X) is considered the antiderivative of f(x) Find Flex) F(x)=√₁² (3+² +4 t) dt F(X)= 3x² + UX 2. F(x) = √7/² sin(e) de F'(x) = sin(x³). 3x² 3x² sin(x³) ((t) 2 3 4 3. F(X) = Sy het dt F'(x) = n(4x).4 - 4 h(4x)] 5. F(x)=√x (t²-t) dt [(3x)²-(3x)]-3-[(2x)²-(2x)]·2=19x²-5x function, s gsh are differentiable then f(t)dt = f(g(x)) · g'(x). & S(x) f(t) dt = f(g(x)) · g'(x) = f(h(x)) - h'(x).
iOS User
Stefan S, iOS User
SuSSan, iOS User
1
Share
Save
Calculus AB
Study note
Isabel Banayad
1 Follower
An introduction to the fundamental theorem of calculus and antiderivatives.
1 Follower
0
0
0
13
all formulas to memorize for AP Calculus AB exam
0
0
6.4 the fundamental thoum of Cole & tummulation interval w/ unknown stop point gives us [a, x], where is a constant & xis an unknown vanable. this as a function looks like FGX) = Sr. Frede 1. let F(x) = So f(t) dt. Find values of table on interval 0²x²5 2) complete tables the disa X 2 3 5 5 5.5 S 4 E(X) 0 2.5 4 a001.5 Sof(t)dt = 0 Sof(t) sof(t) Sof Saf Sof -1- this is called an acrymulanya fuachan Fundamental theemm of raichtes if a is constant's f is a continuous cunction, then d &/ S₁ f(t) dt = $(30 F(x)=√x Stdt 5(x)·() - 5(-x)•(-D) = 5X-5x =JD1 svariations of ftc if a is constant, & is a continuous $19(x) derivatives & integrals are inverses of each other, they cancel each other out, just like multiplication & division in example 1, the graph of f is the derivative of F(x). So F(X) is considered the antiderivative of f(x) Find Flex) F(x)=√₁² (3+² +4 t) dt F(X)= 3x² + UX 2. F(x) = √7/² sin(e) de F'(x) = sin(x³). 3x² 3x² sin(x³) ((t) 2 3 4 3. F(X) = Sy het dt F'(x) = n(4x).4 - 4 h(4x)] 5. F(x)=√x (t²-t) dt [(3x)²-(3x)]-3-[(2x)²-(2x)]·2=19x²-5x function, s gsh are differentiable then f(t)dt = f(g(x)) · g'(x). & S(x) f(t) dt = f(g(x)) · g'(x) = f(h(x)) - h'(x).
6.4 the fundamental thoum of Cole & tummulation interval w/ unknown stop point gives us [a, x], where is a constant & xis an unknown vanable. this as a function looks like FGX) = Sr. Frede 1. let F(x) = So f(t) dt. Find values of table on interval 0²x²5 2) complete tables the disa X 2 3 5 5 5.5 S 4 E(X) 0 2.5 4 a001.5 Sof(t)dt = 0 Sof(t) sof(t) Sof Saf Sof -1- this is called an acrymulanya fuachan Fundamental theemm of raichtes if a is constant's f is a continuous cunction, then d &/ S₁ f(t) dt = $(30 F(x)=√x Stdt 5(x)·() - 5(-x)•(-D) = 5X-5x =JD1 svariations of ftc if a is constant, & is a continuous $19(x) derivatives & integrals are inverses of each other, they cancel each other out, just like multiplication & division in example 1, the graph of f is the derivative of F(x). So F(X) is considered the antiderivative of f(x) Find Flex) F(x)=√₁² (3+² +4 t) dt F(X)= 3x² + UX 2. F(x) = √7/² sin(e) de F'(x) = sin(x³). 3x² 3x² sin(x³) ((t) 2 3 4 3. F(X) = Sy het dt F'(x) = n(4x).4 - 4 h(4x)] 5. F(x)=√x (t²-t) dt [(3x)²-(3x)]-3-[(2x)²-(2x)]·2=19x²-5x function, s gsh are differentiable then f(t)dt = f(g(x)) · g'(x). & S(x) f(t) dt = f(g(x)) · g'(x) = f(h(x)) - h'(x).
iOS User
Stefan S, iOS User
SuSSan, iOS User