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Raoult's Law with Examples
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RA OULT'S LAW • Ass umptions 4) Vapor phase is in the ideal gas state 2) Liquid phase is in ideal solution Application 1) LOW to moderate pressures 2) Species are chemically similar lex. benzene / toluene, ethanol /propanci) • Limitations 1) Appli cable only to species of 2) Applicable то temp er atures below Yi = vapor - phase Xi = .yip = States that the partial vapor OF each componenti in an ideal mixture is dependent on liquid phase m Fraction OF the component multiplied by its pure component vapor pressure. pressure the at a certain temperature. Yip = Xi Pisat | Pisat mole Fraction liquid-phase mole Fraction partial pressure OF Species i in vapor state * P= P₁ + P₂ P₁ = Xipsat PR = X₂P ₂² at known vapor pressure critical Temperature THE CHL CULA TIONS USING RAOULT'S LAW Bubl P.: calculate {yi} and P₁ given Dew P : Calculate Xi} Bubl T.: calculate {yip Dew r Calculate and p , given and T given {xi} and T • given • Y₁P = xipisat Ziyip = Zixi pisat PZigi = Xipisat vapor pressure of the pure species i in the vapor phase. P= Zixi pisat {xi} and T fyi}. and T Exi}. and P hyip and P the. For a binary system P = x1 P₁ sat + x₂ Pasat P= XI Pisat + (1-кі) Pisar P= xipisat + Posat -X₁ Pq sat [P= XI (PISO+ - P₁ sat) + Pusat Anto ine Equation For Vapor In pisat Given: mixture T: 75 °C y, and P Reqd: Join: 1) EXAMPLE: consider a at temperature OF Values OF .XI.. From In Pisar in pisai where : Pisat Ai, Bi, .ci .= T...
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Alternative transcript:
= Temp erature In P₂ sall 0 0.22 0:4 0.6 0.8 1.0 @ x₁ = 0.2 Ai the values OF Ai Antoine P₁ sat 83.21 кра ·P₂501 = 41.98 kpa Vi 0 OF ace to nitrile (1) / nitro methane (2) 14.84150 Bi T1CI vapor 14-7513 @ diff. values OF X₁ TICI 0.331. 0.569 0.748 0-888. 1.0 Pressures OF Pure Species YIP XIPIS at y( 50.2nlº) = (on)($9.!) 4₁ = 0.331 . egn mixture Of acetonitrile (1) / nitrome thane (2). 15 °C - Determine the yi alld P at different p= ૦.૧( % 0.1-_ષા વ૬) 1 પ!. વધુ P= 30. 226 KPQ pressure OF Pure upecies constants Antoine 3413. 10 75 + 250.523 P 41.98 3331. 70 75+ 227.000 Egn: 50.226 58.41 66.712 For species I T4. qu 83.221. (Acetonitrile). (nitro me thane). P = X₁ (Disar posat ) + P₂ sat @ X₁ = D P = ૦ ( ૪૦. ૧) - |-૧૬) ૧ પા. ૧૬ [P= 41.98 KPG VIP = X₁P₁ sat ૫ (પા.૧%) = (o)( ºv. 2) y₁ = 0 EXAMPLE 2 Given .a. aty₁ = 0.600. pressure P. OF X₁. and xe. Given.: mixture. OF T= 75°C Redd. Determine X₁., Xn Join: Y₁ P = · XiPi Xi =. P= yip. Pisat • X₁ = For binary system XI +. X₂ = 1 YIP Pj Sat P. Y₁ p, sat .Y1 = 0.00 @.75 °C. P= tosld mix ture OF . ace. tonitrile. (1) and. T= 15°C, determine . the solution and t X₁ = 0.43) X₂ = 0.509 sat угр. Prsat ace tonitrile (1) / nitro me thane (2) P OF Y2 .P₂ sat Prsat 0.40. 89.21.kPa P= 59: 741 KPQ + the . 0.00 (59.741 kPa) ·83.21 mixture (1-.0.00). 41.98.KAG . and P= the. the liquid phase composition.s Pisat 1 nitro, methane. (2) corresponding. _Y? Prsat DEW P CALCULATION.
These notes focus on Raoult's Law, which includes a clear definition, the interplay with Henry's Law, and its role in ideal solutions. It also shows the formula and how it is applied.
These notes focus on Raoult's Law, which includes a clear definition, the interplay with Henry's Law, and its role in ideal solutions. It also shows the formula and how it is applied.
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RA OULT'S LAW • Ass umptions 4) Vapor phase is in the ideal gas state 2) Liquid phase is in ideal solution Application 1) LOW to moderate pressures 2) Species are chemically similar lex. benzene / toluene, ethanol /propanci) • Limitations 1) Appli cable only to species of 2) Applicable то temp er atures below Yi = vapor - phase Xi = .yip = States that the partial vapor OF each componenti in an ideal mixture is dependent on liquid phase m Fraction OF the component multiplied by its pure component vapor pressure. pressure the at a certain temperature. Yip = Xi Pisat | Pisat mole Fraction liquid-phase mole Fraction partial pressure OF Species i in vapor state * P= P₁ + P₂ P₁ = Xipsat PR = X₂P ₂² at known vapor pressure critical Temperature THE CHL CULA TIONS USING RAOULT'S LAW Bubl P.: calculate {yi} and P₁ given Dew P : Calculate Xi} Bubl T.: calculate {yip Dew r Calculate and p , given and T given {xi} and T • given • Y₁P = xipisat Ziyip = Zixi pisat PZigi = Xipisat vapor pressure of the pure species i in the vapor phase. P= Zixi pisat {xi} and T fyi}. and T Exi}. and P hyip and P the. For a binary system P = x1 P₁ sat + x₂ Pasat P= XI Pisat + (1-кі) Pisar P= xipisat + Posat -X₁ Pq sat [P= XI (PISO+ - P₁ sat) + Pusat Anto ine Equation For Vapor In pisat Given: mixture T: 75 °C y, and P Reqd: Join: 1) EXAMPLE: consider a at temperature OF Values OF .XI.. From In Pisar in pisai where : Pisat Ai, Bi, .ci .= T...
RA OULT'S LAW • Ass umptions 4) Vapor phase is in the ideal gas state 2) Liquid phase is in ideal solution Application 1) LOW to moderate pressures 2) Species are chemically similar lex. benzene / toluene, ethanol /propanci) • Limitations 1) Appli cable only to species of 2) Applicable то temp er atures below Yi = vapor - phase Xi = .yip = States that the partial vapor OF each componenti in an ideal mixture is dependent on liquid phase m Fraction OF the component multiplied by its pure component vapor pressure. pressure the at a certain temperature. Yip = Xi Pisat | Pisat mole Fraction liquid-phase mole Fraction partial pressure OF Species i in vapor state * P= P₁ + P₂ P₁ = Xipsat PR = X₂P ₂² at known vapor pressure critical Temperature THE CHL CULA TIONS USING RAOULT'S LAW Bubl P.: calculate {yi} and P₁ given Dew P : Calculate Xi} Bubl T.: calculate {yip Dew r Calculate and p , given and T given {xi} and T • given • Y₁P = xipisat Ziyip = Zixi pisat PZigi = Xipisat vapor pressure of the pure species i in the vapor phase. P= Zixi pisat {xi} and T fyi}. and T Exi}. and P hyip and P the. For a binary system P = x1 P₁ sat + x₂ Pasat P= XI Pisat + (1-кі) Pisar P= xipisat + Posat -X₁ Pq sat [P= XI (PISO+ - P₁ sat) + Pusat Anto ine Equation For Vapor In pisat Given: mixture T: 75 °C y, and P Reqd: Join: 1) EXAMPLE: consider a at temperature OF Values OF .XI.. From In Pisar in pisai where : Pisat Ai, Bi, .ci .= T...
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SuSSan, iOS User
Love this App ❤️, I use it basically all the time whenever I'm studying
Alternative transcript:
= Temp erature In P₂ sall 0 0.22 0:4 0.6 0.8 1.0 @ x₁ = 0.2 Ai the values OF Ai Antoine P₁ sat 83.21 кра ·P₂501 = 41.98 kpa Vi 0 OF ace to nitrile (1) / nitro methane (2) 14.84150 Bi T1CI vapor 14-7513 @ diff. values OF X₁ TICI 0.331. 0.569 0.748 0-888. 1.0 Pressures OF Pure Species YIP XIPIS at y( 50.2nlº) = (on)($9.!) 4₁ = 0.331 . egn mixture Of acetonitrile (1) / nitrome thane (2). 15 °C - Determine the yi alld P at different p= ૦.૧( % 0.1-_ષા વ૬) 1 પ!. વધુ P= 30. 226 KPQ pressure OF Pure upecies constants Antoine 3413. 10 75 + 250.523 P 41.98 3331. 70 75+ 227.000 Egn: 50.226 58.41 66.712 For species I T4. qu 83.221. (Acetonitrile). (nitro me thane). P = X₁ (Disar posat ) + P₂ sat @ X₁ = D P = ૦ ( ૪૦. ૧) - |-૧૬) ૧ પા. ૧૬ [P= 41.98 KPG VIP = X₁P₁ sat ૫ (પા.૧%) = (o)( ºv. 2) y₁ = 0 EXAMPLE 2 Given .a. aty₁ = 0.600. pressure P. OF X₁. and xe. Given.: mixture. OF T= 75°C Redd. Determine X₁., Xn Join: Y₁ P = · XiPi Xi =. P= yip. Pisat • X₁ = For binary system XI +. X₂ = 1 YIP Pj Sat P. Y₁ p, sat .Y1 = 0.00 @.75 °C. P= tosld mix ture OF . ace. tonitrile. (1) and. T= 15°C, determine . the solution and t X₁ = 0.43) X₂ = 0.509 sat угр. Prsat ace tonitrile (1) / nitro me thane (2) P OF Y2 .P₂ sat Prsat 0.40. 89.21.kPa P= 59: 741 KPQ + the . 0.00 (59.741 kPa) ·83.21 mixture (1-.0.00). 41.98.KAG . and P= the. the liquid phase composition.s Pisat 1 nitro, methane. (2) corresponding. _Y? Prsat DEW P CALCULATION.