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PIPE Pipe wall t tm = tp + C Pd tp: 2(SE IPY) C:- sum of mechanical allowances (thread depth) plus corrosion erosion allowance P: -internal gauge design P d: pipe outside D S:- basic allowable stress for pipe material E: - casting quality factor Y: - T factor Schd No Ps: 0₂: - - Ps x 1000 % P safe working safe working stress Example 1: Estimate the safe working Pressure for a 4 in. (100 mm) dia., schd 40 pipe, SA 53 carbon steel, butt- welded, working T 100°C. The maximum allowable stress for buft-welded steel pipe up to 120 °C is 11, 700 psi (79.6 N/mm²). V GIVEN. Os = 11, 700 psi Schd 40 pipe, SA 53 CS REQ'O: Ps SOLUTION: Schd. No. = 40 = Ps x 1000 ÚS Ps x 1000 4,700 poi Ps 468 psi = ECONOMIC PIPE DIAMETER * A106 Carbon Steel Pipe: 25 to 200 mm, di,optimum = 0.664 G0.51 -0.36 Р = 0.534 G 0.93 p²² 250 to 600 mm, di, optimumu = 0.93-0.30 * 304 Stainless Steel Pipe 25 to 200 mmu, di, optimum = 0.550G0.49 -0.35 250 to 600 mm, di, optimum = 0.463 G0·43p-0.31 Example 2. flow rate of 10 Estimate the optimum pipe diameter for a water • kgls, at 20 dego. Carbon steel pipe will be used. Dersity of water 1000 kg/m² GIVEN *Carbon steel pipe m 1₂0 = 10 kgls T = 20°C PH:₂0 = 1000 kg/m³ REQ'D. di,optimumu SOLUTION: For Carbon Steel Pipe: 25 to 200 m: di,optimum = 0 669 GⓇ = di, optimum = 0.664 (10)0.5¹ (1000 kg/m³) -0.36 di,...
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Alternative transcript:
optimum =0.1787m) = 178.7179 mm x OS 4THR di, optimum = 7.0361 in (it is not a standard pipe 5126) * Look for the closest standard pipe sizes (you may use your handbook) which is either 6 or Sº Try 6'sch 40 pipe which has on 10 of 4.045 in Re = Dvp Op Q Op Q w Re=₁ 051 -0.36 P WA 4 (10 kg/s) (1000 kg/m³) IT (1.1x10-2) (6.065 in x 0.0254) Ns. m Re 75161720.47 7 4000 ✓ flow is turbulent so the pipe size is acceptable. Example 2.1 GIVEN: 500 gal/min PH₂0 = 1000 kglnt 4QP = 0² Tud REQ'D: V SOLUTION: A10G Carbon steel pipe * 25 - 200 mm: di, optimumu = 0.664 60.51,-0.36 di,optimum =0.664(500x. 3.784 Igal min (1000 kg/m³)-8:30 10 12 DA di,optimunt = 0.02 m = 320 mmu di, * 250 - 600 mm, optimum 1=0.334 G0.43 -0.3 P di, optimum = 0.534 (500_gal x 2.785 m² ૩. ૧૩ 1x I min 403 (1000 kg/m³) 38 gal du, optimum = 0.296 m = 296 mm³ = 11.65¹ schd 20: 10 = 10.020 11 A 11.65 ·X ID= - 1 BAT 051 605 N Re Re= Re = 4PQ Ħ UD Re Re = 156091 (500_gal min DNP DP Q - DR. Q_DP A u " N MU X 4 (1000 kg/m³) (500 g (1000 kg/m³) (10x) 5000x3.785 £ ·X gal V = 0.62 m/s Assume √ = 1 m/s Q = AN = ID²N I min 603 ·X. (1011 X 10-as) (IT) (10.02 in x 0.0254AU) 119 Q 3.785 L 2 II (10.02 in x 0.0254 m₂) ² 4 IJA Igal I DAINT GOS = 195953.2962 X ·X D = 0. 2004 m = 7.8898 in <₁ T Q I D² 4 ·3.785€ Im ·X тдят Im 103 t x 1 mm²³) = (0²) (im/s) 10 = 6.065 in 8" 10 = 7.981 in 1011 x 10-6 Pa. S Design velocity = (7 981 *mx 25.4 mm Jin Flat 1024) DNP _ (7.981 in x 0.0254 m) (500 gal x 1 min x 3.78 5.-t ·X in min 605 I gat W (7.981x0.0254m) ² 10 5 X ) (1000 kg/m³) imv) (0.06) +0.4m/s (
Sample problem with computations regarding pipes
Sample problem with computations regarding pipes
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PIPE Pipe wall t tm = tp + C Pd tp: 2(SE IPY) C:- sum of mechanical allowances (thread depth) plus corrosion erosion allowance P: -internal gauge design P d: pipe outside D S:- basic allowable stress for pipe material E: - casting quality factor Y: - T factor Schd No Ps: 0₂: - - Ps x 1000 % P safe working safe working stress Example 1: Estimate the safe working Pressure for a 4 in. (100 mm) dia., schd 40 pipe, SA 53 carbon steel, butt- welded, working T 100°C. The maximum allowable stress for buft-welded steel pipe up to 120 °C is 11, 700 psi (79.6 N/mm²). V GIVEN. Os = 11, 700 psi Schd 40 pipe, SA 53 CS REQ'O: Ps SOLUTION: Schd. No. = 40 = Ps x 1000 ÚS Ps x 1000 4,700 poi Ps 468 psi = ECONOMIC PIPE DIAMETER * A106 Carbon Steel Pipe: 25 to 200 mm, di,optimum = 0.664 G0.51 -0.36 Р = 0.534 G 0.93 p²² 250 to 600 mm, di, optimumu = 0.93-0.30 * 304 Stainless Steel Pipe 25 to 200 mmu, di, optimum = 0.550G0.49 -0.35 250 to 600 mm, di, optimum = 0.463 G0·43p-0.31 Example 2. flow rate of 10 Estimate the optimum pipe diameter for a water • kgls, at 20 dego. Carbon steel pipe will be used. Dersity of water 1000 kg/m² GIVEN *Carbon steel pipe m 1₂0 = 10 kgls T = 20°C PH:₂0 = 1000 kg/m³ REQ'D. di,optimumu SOLUTION: For Carbon Steel Pipe: 25 to 200 m: di,optimum = 0 669 GⓇ = di, optimum = 0.664 (10)0.5¹ (1000 kg/m³) -0.36 di,...
PIPE Pipe wall t tm = tp + C Pd tp: 2(SE IPY) C:- sum of mechanical allowances (thread depth) plus corrosion erosion allowance P: -internal gauge design P d: pipe outside D S:- basic allowable stress for pipe material E: - casting quality factor Y: - T factor Schd No Ps: 0₂: - - Ps x 1000 % P safe working safe working stress Example 1: Estimate the safe working Pressure for a 4 in. (100 mm) dia., schd 40 pipe, SA 53 carbon steel, butt- welded, working T 100°C. The maximum allowable stress for buft-welded steel pipe up to 120 °C is 11, 700 psi (79.6 N/mm²). V GIVEN. Os = 11, 700 psi Schd 40 pipe, SA 53 CS REQ'O: Ps SOLUTION: Schd. No. = 40 = Ps x 1000 ÚS Ps x 1000 4,700 poi Ps 468 psi = ECONOMIC PIPE DIAMETER * A106 Carbon Steel Pipe: 25 to 200 mm, di,optimum = 0.664 G0.51 -0.36 Р = 0.534 G 0.93 p²² 250 to 600 mm, di, optimumu = 0.93-0.30 * 304 Stainless Steel Pipe 25 to 200 mmu, di, optimum = 0.550G0.49 -0.35 250 to 600 mm, di, optimum = 0.463 G0·43p-0.31 Example 2. flow rate of 10 Estimate the optimum pipe diameter for a water • kgls, at 20 dego. Carbon steel pipe will be used. Dersity of water 1000 kg/m² GIVEN *Carbon steel pipe m 1₂0 = 10 kgls T = 20°C PH:₂0 = 1000 kg/m³ REQ'D. di,optimumu SOLUTION: For Carbon Steel Pipe: 25 to 200 m: di,optimum = 0 669 GⓇ = di, optimum = 0.664 (10)0.5¹ (1000 kg/m³) -0.36 di,...
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Knowunity is the # 1 ranked education app in five European countries
Knowunity was a featured story by Apple and has consistently topped the app store charts within the education category in Germany, Italy, Poland, Switzerland and United Kingdom. Join Knowunity today and help millions of students around the world.
Still not sure? Look at what your fellow peers are saying...
iOS User
I love this app so much [...] I recommend Knowunity to everyone!!! I went from a C to an A with it :D
Stefan S, iOS User
The application is very simple and well designed. So far I have found what I was looking for :D
SuSSan, iOS User
Love this App ❤️, I use it basically all the time whenever I'm studying
Alternative transcript:
optimum =0.1787m) = 178.7179 mm x OS 4THR di, optimum = 7.0361 in (it is not a standard pipe 5126) * Look for the closest standard pipe sizes (you may use your handbook) which is either 6 or Sº Try 6'sch 40 pipe which has on 10 of 4.045 in Re = Dvp Op Q Op Q w Re=₁ 051 -0.36 P WA 4 (10 kg/s) (1000 kg/m³) IT (1.1x10-2) (6.065 in x 0.0254) Ns. m Re 75161720.47 7 4000 ✓ flow is turbulent so the pipe size is acceptable. Example 2.1 GIVEN: 500 gal/min PH₂0 = 1000 kglnt 4QP = 0² Tud REQ'D: V SOLUTION: A10G Carbon steel pipe * 25 - 200 mm: di, optimumu = 0.664 60.51,-0.36 di,optimum =0.664(500x. 3.784 Igal min (1000 kg/m³)-8:30 10 12 DA di,optimunt = 0.02 m = 320 mmu di, * 250 - 600 mm, optimum 1=0.334 G0.43 -0.3 P di, optimum = 0.534 (500_gal x 2.785 m² ૩. ૧૩ 1x I min 403 (1000 kg/m³) 38 gal du, optimum = 0.296 m = 296 mm³ = 11.65¹ schd 20: 10 = 10.020 11 A 11.65 ·X ID= - 1 BAT 051 605 N Re Re= Re = 4PQ Ħ UD Re Re = 156091 (500_gal min DNP DP Q - DR. Q_DP A u " N MU X 4 (1000 kg/m³) (500 g (1000 kg/m³) (10x) 5000x3.785 £ ·X gal V = 0.62 m/s Assume √ = 1 m/s Q = AN = ID²N I min 603 ·X. (1011 X 10-as) (IT) (10.02 in x 0.0254AU) 119 Q 3.785 L 2 II (10.02 in x 0.0254 m₂) ² 4 IJA Igal I DAINT GOS = 195953.2962 X ·X D = 0. 2004 m = 7.8898 in <₁ T Q I D² 4 ·3.785€ Im ·X тдят Im 103 t x 1 mm²³) = (0²) (im/s) 10 = 6.065 in 8" 10 = 7.981 in 1011 x 10-6 Pa. S Design velocity = (7 981 *mx 25.4 mm Jin Flat 1024) DNP _ (7.981 in x 0.0254 m) (500 gal x 1 min x 3.78 5.-t ·X in min 605 I gat W (7.981x0.0254m) ² 10 5 X ) (1000 kg/m³) imv) (0.06) +0.4m/s (