Download in
Google Play
157
Share
Save
Sign up
Access to all documents
Join milions of students
Improve your grades
By signing up you accept Terms of Service and Privacy Policy
H Pythagoras a 0 (0) opposit b C x adjacent (a) Trigonometry •h sin x Y cos x x hypotenuse (n) 0 SH tan x a 4cm/ a²+ b²=c² x 5cm Soc h Calculate the length of x to 1 dp • perpendicular height b²=72-3²= 40 0° 0 1 0 O • a 30° 글 6cm h • hypotenuse → longest side, opposite the right angle. · hypotenuse is always C. •a and b are any of the remaining sides. C A longest side, opposite the right angle. opposite the angle given (x). next to the angue given CoC). H b=√40 45° • to calculate an angle use the inverse function on your calculator. +eg fan to find out tan 0 Calculate YZ to 1dp 60° √3 0 T A - 90° 1 0 X -hyp of larger triangle (√40)2 +62 = 76 x = √76= 8.7 cm. ratibe 1 a is known, h must be calculated, use c 5 = 5.51... YZ = 5.5 cm COS 25 - exact trig Calculate ac to 1dp →a and h are known, use CH. A √2 gdj cos1 = cos(4) = 0.6 = 48.2° X= 48.2° UNIT 4 30⁰ 2 √√√3 Kedish coff 1 60 1 30° 2 2
iOS User
Stefan S, iOS User
SuSSan, iOS User
157
Share
Save
An Pham
65 Followers
Basics of pythag and trig
65 Followers
203
Explains how to do basic trigonometry with examples. This is aimed towards year 10 and 11 GCSE maths students, mainly foundation tier, however is applicable to higher tier who struggle understanding the topic
0
Higher maths Pythagoras theorem helping hand
43
This is one of 2 Mind maps I have completed, I hope it helps someone out as I find it useful to have all the elements of maths in one place in a simple way. I do the higher paper.
337
NOTES
28
These notes include; Pythagoras, Circles/Parts of a circle and the formulas, Trigonometry, Histograms, Parallel Lines cut by a Transversal, Geometry, Angles around a point and Alternate, Allied and corresponding Angles.
47
Maths, Trigonomatry
H Pythagoras a 0 (0) opposit b C x adjacent (a) Trigonometry •h sin x Y cos x x hypotenuse (n) 0 SH tan x a 4cm/ a²+ b²=c² x 5cm Soc h Calculate the length of x to 1 dp • perpendicular height b²=72-3²= 40 0° 0 1 0 O • a 30° 글 6cm h • hypotenuse → longest side, opposite the right angle. · hypotenuse is always C. •a and b are any of the remaining sides. C A longest side, opposite the right angle. opposite the angle given (x). next to the angue given CoC). H b=√40 45° • to calculate an angle use the inverse function on your calculator. +eg fan to find out tan 0 Calculate YZ to 1dp 60° √3 0 T A - 90° 1 0 X -hyp of larger triangle (√40)2 +62 = 76 x = √76= 8.7 cm. ratibe 1 a is known, h must be calculated, use c 5 = 5.51... YZ = 5.5 cm COS 25 - exact trig Calculate ac to 1dp →a and h are known, use CH. A √2 gdj cos1 = cos(4) = 0.6 = 48.2° X= 48.2° UNIT 4 30⁰ 2 √√√3 Kedish coff 1 60 1 30° 2 2
H Pythagoras a 0 (0) opposit b C x adjacent (a) Trigonometry •h sin x Y cos x x hypotenuse (n) 0 SH tan x a 4cm/ a²+ b²=c² x 5cm Soc h Calculate the length of x to 1 dp • perpendicular height b²=72-3²= 40 0° 0 1 0 O • a 30° 글 6cm h • hypotenuse → longest side, opposite the right angle. · hypotenuse is always C. •a and b are any of the remaining sides. C A longest side, opposite the right angle. opposite the angle given (x). next to the angue given CoC). H b=√40 45° • to calculate an angle use the inverse function on your calculator. +eg fan to find out tan 0 Calculate YZ to 1dp 60° √3 0 T A - 90° 1 0 X -hyp of larger triangle (√40)2 +62 = 76 x = √76= 8.7 cm. ratibe 1 a is known, h must be calculated, use c 5 = 5.51... YZ = 5.5 cm COS 25 - exact trig Calculate ac to 1dp →a and h are known, use CH. A √2 gdj cos1 = cos(4) = 0.6 = 48.2° X= 48.2° UNIT 4 30⁰ 2 √√√3 Kedish coff 1 60 1 30° 2 2
iOS User
Stefan S, iOS User
SuSSan, iOS User