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Name: Topic: Main Ideas/Questions ARC LENGTH r 1 Notes/Examples Arc Length Formula: 1. 3. x = degree measure of arc C = circumference (C= 2πr; C = Td) Directions: Find the length of each bolded arc to the nearest hundredth. 2. l=38.2TT 15 360 6 m 142° M 162* The length of an arc is a portion of the circumference. 107* D 4 cm E 15 B 8 R 68° 112° 15.22 cm 5. If EB = 15 centimeters, find the length of CD. l=112.30 TT 360 = 3360 TT 360 e l=107-21T6 360 P = 1284T 360 с Date: X-C 360 ≈11.21 m 1= 218.274 360 Class: =174475 360 6. If NR = 8 feet, find the length of NMP. 18 N 4. 15 in 288* 9.5 ft ~29.32 cm 1 = 198.16TT 360 = 3168TT 360 ~27.65 ft 38° = 1140 TT 360 ~9.95 in l= 12.2119.5 340 = 1368 TT 360 ≈ 11.94 ft Ⓒ Gina Wilson (All Things Algebra, LLC), 2015-2019 APPLICATIONS 7. If VS = 12 meters, find the length of UT. R V 53⁰ U 127 W/ K P 37° T 21 8. IfJH = 21 inches, find the length of KJG. G l=334-21 360 = 7014 T 360 59° 85 E 47° 80° 9. If FG = 27 yards, find the length of FED. C 128 W H G I S D 10. If WS = 4.5 millimeters, find the length of TS. 2 31 l=37-12TT R 360 = 444 T 360 280 = X 150 TT 360 l=233.54T 360 = 125821T 360 l=97.9TT 360 = 8131 360 1280TT 360 ~3.87m ~61.21 in 11. A 16-inch pendulum swings through an angle of 40°. How far does the tip of the pendulum travel in a single swing? l=40-2TT 16 360 100800 150TT 109.8 yd ~7.62 mm 12. A car entered a roundabout from Mason Avenue, traveled 280 feet, then turned onto Perry Street. If the roundabout has a diameter of 150 feet, find the angle of rotation to the nearest degree the car traveled. ~11.17...
iOS User
Stefan S, iOS User
SuSSan, iOS User
in X 150 TT 150TT X = 214° Ⓒ Gina Wilson (All Things Algebra, LLC), 2015-2019
U10L3 Arc Lengths Notes
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U10L3 Arc Lengths Solutions
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area of circle notes and area of sector notes with examples
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Study guide for all things circle
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This is a finished and completed worksheet that applies very helpful information for the subject.
Name: Topic: Main Ideas/Questions ARC LENGTH r 1 Notes/Examples Arc Length Formula: 1. 3. x = degree measure of arc C = circumference (C= 2πr; C = Td) Directions: Find the length of each bolded arc to the nearest hundredth. 2. l=38.2TT 15 360 6 m 142° M 162* The length of an arc is a portion of the circumference. 107* D 4 cm E 15 B 8 R 68° 112° 15.22 cm 5. If EB = 15 centimeters, find the length of CD. l=112.30 TT 360 = 3360 TT 360 e l=107-21T6 360 P = 1284T 360 с Date: X-C 360 ≈11.21 m 1= 218.274 360 Class: =174475 360 6. If NR = 8 feet, find the length of NMP. 18 N 4. 15 in 288* 9.5 ft ~29.32 cm 1 = 198.16TT 360 = 3168TT 360 ~27.65 ft 38° = 1140 TT 360 ~9.95 in l= 12.2119.5 340 = 1368 TT 360 ≈ 11.94 ft Ⓒ Gina Wilson (All Things Algebra, LLC), 2015-2019 APPLICATIONS 7. If VS = 12 meters, find the length of UT. R V 53⁰ U 127 W/ K P 37° T 21 8. IfJH = 21 inches, find the length of KJG. G l=334-21 360 = 7014 T 360 59° 85 E 47° 80° 9. If FG = 27 yards, find the length of FED. C 128 W H G I S D 10. If WS = 4.5 millimeters, find the length of TS. 2 31 l=37-12TT R 360 = 444 T 360 280 = X 150 TT 360 l=233.54T 360 = 125821T 360 l=97.9TT 360 = 8131 360 1280TT 360 ~3.87m ~61.21 in 11. A 16-inch pendulum swings through an angle of 40°. How far does the tip of the pendulum travel in a single swing? l=40-2TT 16 360 100800 150TT 109.8 yd ~7.62 mm 12. A car entered a roundabout from Mason Avenue, traveled 280 feet, then turned onto Perry Street. If the roundabout has a diameter of 150 feet, find the angle of rotation to the nearest degree the car traveled. ~11.17...
Name: Topic: Main Ideas/Questions ARC LENGTH r 1 Notes/Examples Arc Length Formula: 1. 3. x = degree measure of arc C = circumference (C= 2πr; C = Td) Directions: Find the length of each bolded arc to the nearest hundredth. 2. l=38.2TT 15 360 6 m 142° M 162* The length of an arc is a portion of the circumference. 107* D 4 cm E 15 B 8 R 68° 112° 15.22 cm 5. If EB = 15 centimeters, find the length of CD. l=112.30 TT 360 = 3360 TT 360 e l=107-21T6 360 P = 1284T 360 с Date: X-C 360 ≈11.21 m 1= 218.274 360 Class: =174475 360 6. If NR = 8 feet, find the length of NMP. 18 N 4. 15 in 288* 9.5 ft ~29.32 cm 1 = 198.16TT 360 = 3168TT 360 ~27.65 ft 38° = 1140 TT 360 ~9.95 in l= 12.2119.5 340 = 1368 TT 360 ≈ 11.94 ft Ⓒ Gina Wilson (All Things Algebra, LLC), 2015-2019 APPLICATIONS 7. If VS = 12 meters, find the length of UT. R V 53⁰ U 127 W/ K P 37° T 21 8. IfJH = 21 inches, find the length of KJG. G l=334-21 360 = 7014 T 360 59° 85 E 47° 80° 9. If FG = 27 yards, find the length of FED. C 128 W H G I S D 10. If WS = 4.5 millimeters, find the length of TS. 2 31 l=37-12TT R 360 = 444 T 360 280 = X 150 TT 360 l=233.54T 360 = 125821T 360 l=97.9TT 360 = 8131 360 1280TT 360 ~3.87m ~61.21 in 11. A 16-inch pendulum swings through an angle of 40°. How far does the tip of the pendulum travel in a single swing? l=40-2TT 16 360 100800 150TT 109.8 yd ~7.62 mm 12. A car entered a roundabout from Mason Avenue, traveled 280 feet, then turned onto Perry Street. If the roundabout has a diameter of 150 feet, find the angle of rotation to the nearest degree the car traveled. ~11.17...
iOS User
Stefan S, iOS User
SuSSan, iOS User
in X 150 TT 150TT X = 214° Ⓒ Gina Wilson (All Things Algebra, LLC), 2015-2019