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U11L8 Volume of Pyramids and Cones Solutions
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Name: Date: 1. ** This is a 2-page document! ** Directions: Find the volume of each figure. Round to the nearest hundredth when necessary. 2. 3 km 22 cm 3. 3.7 ft- 5. 14 cm 7. 19 m 7.2 in 14 cm B=12(12)(3.7) = 22.2 V=13(22.2) (8) = 59.2 ft3/ 73 B ft 12 ft 12 m Bell: B = 14² = 196 v=13 (196)(22) 1437.33 cm3 9.7 in V=Y3TT(9.5)² (12) = 361TT =1134.11 m3 7.2²+x²=9.1² x2=42.25 X=6.5 B=13²=169 V = "3 (169) (7.2) = 405.6 in 3 8 km 4. Unit 11: Volume & Surface Area Homework 8: Volume of Pyramids & Cones 6. 8. 5.7 yd 9 yd B = 9(23) = 207 V= 13 (201)(5.7) = As 23 yd 16 ft 16 ft 8√3 11 mm V = 1/3 TT (3)².8 =24 TT 8 mm B = 110 mm² V=43 (110) (11) =403.33 mm3/ 24 ft = 16 ft 75.4km3 393.3 yd 3 B=12 (16)(16√3) = 110.85 V=1/3(110.85) (24) 886.8f+3) = Gina Wilson (All Things Algebra), 2015 9. 26.7 km 11.7 km x² +11.7²2=26.7² x²=576 X=24 X=24 18 in- 24 ft 9 ft 15 km 10 in 18 in H 15 ft 11. Find the volume of the shaded solid below. V Large V small = 1/3 TT (4) ² (10) = 160T .15 in B=12(11-7)(24) = 140.4 V=13(140.4)(15) 702 km3 12. Find the total volume of the solid below. 10 ft 10. 17.3 cm 1x=165 10.4 cm - 5.2²+x²=11.32 x²=272.25 X=165 = 1/3 TT (9)²(25) = 675T B = 1/2 (9) (12) = 54 V = 54 (10) = 540 14.4 12 ft (2) V = 1/3 (54) (14) = 252 V=Y3TT(5.2)² (16.5) = 446.16 T 3 V=2120-58-167.55 = 1953.03 in 3 =467.22 cm3 = 2120.58 = 167.55 V = 540 +252 = 192 ft 3 13. A cone with a radius of 6 meters has a volume of...
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Alternative transcript:
542.87 m³. Find the slant height of the cone. 6 542.81= = 1/3 TT (6) ² 542.87 = 12TTh 14.4 = h 62+14.4² = 1² 243.36 =12 15.6m=e Gina Wilson Things Algebra), 2015
U11L8 Volume of Pyramids and Cones Solutions
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Name: Date: 1. ** This is a 2-page document! ** Directions: Find the volume of each figure. Round to the nearest hundredth when necessary. 2. 3 km 22 cm 3. 3.7 ft- 5. 14 cm 7. 19 m 7.2 in 14 cm B=12(12)(3.7) = 22.2 V=13(22.2) (8) = 59.2 ft3/ 73 B ft 12 ft 12 m Bell: B = 14² = 196 v=13 (196)(22) 1437.33 cm3 9.7 in V=Y3TT(9.5)² (12) = 361TT =1134.11 m3 7.2²+x²=9.1² x2=42.25 X=6.5 B=13²=169 V = "3 (169) (7.2) = 405.6 in 3 8 km 4. Unit 11: Volume & Surface Area Homework 8: Volume of Pyramids & Cones 6. 8. 5.7 yd 9 yd B = 9(23) = 207 V= 13 (201)(5.7) = As 23 yd 16 ft 16 ft 8√3 11 mm V = 1/3 TT (3)².8 =24 TT 8 mm B = 110 mm² V=43 (110) (11) =403.33 mm3/ 24 ft = 16 ft 75.4km3 393.3 yd 3 B=12 (16)(16√3) = 110.85 V=1/3(110.85) (24) 886.8f+3) = Gina Wilson (All Things Algebra), 2015 9. 26.7 km 11.7 km x² +11.7²2=26.7² x²=576 X=24 X=24 18 in- 24 ft 9 ft 15 km 10 in 18 in H 15 ft 11. Find the volume of the shaded solid below. V Large V small = 1/3 TT (4) ² (10) = 160T .15 in B=12(11-7)(24) = 140.4 V=13(140.4)(15) 702 km3 12. Find the total volume of the solid below. 10 ft 10. 17.3 cm 1x=165 10.4 cm - 5.2²+x²=11.32 x²=272.25 X=165 = 1/3 TT (9)²(25) = 675T B = 1/2 (9) (12) = 54 V = 54 (10) = 540 14.4 12 ft (2) V = 1/3 (54) (14) = 252 V=Y3TT(5.2)² (16.5) = 446.16 T 3 V=2120-58-167.55 = 1953.03 in 3 =467.22 cm3 = 2120.58 = 167.55 V = 540 +252 = 192 ft 3 13. A cone with a radius of 6 meters has a volume of...
Name: Date: 1. ** This is a 2-page document! ** Directions: Find the volume of each figure. Round to the nearest hundredth when necessary. 2. 3 km 22 cm 3. 3.7 ft- 5. 14 cm 7. 19 m 7.2 in 14 cm B=12(12)(3.7) = 22.2 V=13(22.2) (8) = 59.2 ft3/ 73 B ft 12 ft 12 m Bell: B = 14² = 196 v=13 (196)(22) 1437.33 cm3 9.7 in V=Y3TT(9.5)² (12) = 361TT =1134.11 m3 7.2²+x²=9.1² x2=42.25 X=6.5 B=13²=169 V = "3 (169) (7.2) = 405.6 in 3 8 km 4. Unit 11: Volume & Surface Area Homework 8: Volume of Pyramids & Cones 6. 8. 5.7 yd 9 yd B = 9(23) = 207 V= 13 (201)(5.7) = As 23 yd 16 ft 16 ft 8√3 11 mm V = 1/3 TT (3)².8 =24 TT 8 mm B = 110 mm² V=43 (110) (11) =403.33 mm3/ 24 ft = 16 ft 75.4km3 393.3 yd 3 B=12 (16)(16√3) = 110.85 V=1/3(110.85) (24) 886.8f+3) = Gina Wilson (All Things Algebra), 2015 9. 26.7 km 11.7 km x² +11.7²2=26.7² x²=576 X=24 X=24 18 in- 24 ft 9 ft 15 km 10 in 18 in H 15 ft 11. Find the volume of the shaded solid below. V Large V small = 1/3 TT (4) ² (10) = 160T .15 in B=12(11-7)(24) = 140.4 V=13(140.4)(15) 702 km3 12. Find the total volume of the solid below. 10 ft 10. 17.3 cm 1x=165 10.4 cm - 5.2²+x²=11.32 x²=272.25 X=165 = 1/3 TT (9)²(25) = 675T B = 1/2 (9) (12) = 54 V = 54 (10) = 540 14.4 12 ft (2) V = 1/3 (54) (14) = 252 V=Y3TT(5.2)² (16.5) = 446.16 T 3 V=2120-58-167.55 = 1953.03 in 3 =467.22 cm3 = 2120.58 = 167.55 V = 540 +252 = 192 ft 3 13. A cone with a radius of 6 meters has a volume of...
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Stefan S, iOS User
The application is very simple and well designed. So far I have found what I was looking for :D
SuSSan, iOS User
Love this App ❤️, I use it basically all the time whenever I'm studying
Alternative transcript:
542.87 m³. Find the slant height of the cone. 6 542.81= = 1/3 TT (6) ² 542.87 = 12TTh 14.4 = h 62+14.4² = 1² 243.36 =12 15.6m=e Gina Wilson Things Algebra), 2015