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000000 D camulative frequency Age No students (F) Class with THI Freq. density cumulative fr O O 20 cumulative Frequency NO NOVO 970 2 10- JUENOTNOS 15 150 15.5 ≤ac16 sa 216.5 ≤94 17.549418.5 2 15.5 2= xx16 X=0.125 O.S ५ 2 6 for first class cumulative frequency is the same as frequency the last class cum. frequecicy must be equal to the total no. umulative frequency is a total number of students below. the upper boundary M=16+X M=16.125 MAGINOTIUNO.S 0.5 12 8 2+6-8,98+8 16 PINNINO IN how peo WOON M VONNSYA SNE O 16 17.5 14 DISTRIBUTION 16 16.5 when we connect each point with a straight segment we get a polygon. 18.5 cf never decreases nighest point is the total no. we can estimate the median usin af. graph. 3 I 3 16 +3=19 19+ 20 median the value where 50%. of data are below and 50%. of data are above
iOS User
Stefan S, iOS User
SuSSan, iOS User
Notes include: - cumulative frequency graph - how to calculate cumulative frequency
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Learn about mean, median, range, standard deviation, and outliers in statistical distributions.
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000000 D camulative frequency Age No students (F) Class with THI Freq. density cumulative fr O O 20 cumulative Frequency NO NOVO 970 2 10- JUENOTNOS 15 150 15.5 ≤ac16 sa 216.5 ≤94 17.549418.5 2 15.5 2= xx16 X=0.125 O.S ५ 2 6 for first class cumulative frequency is the same as frequency the last class cum. frequecicy must be equal to the total no. umulative frequency is a total number of students below. the upper boundary M=16+X M=16.125 MAGINOTIUNO.S 0.5 12 8 2+6-8,98+8 16 PINNINO IN how peo WOON M VONNSYA SNE O 16 17.5 14 DISTRIBUTION 16 16.5 when we connect each point with a straight segment we get a polygon. 18.5 cf never decreases nighest point is the total no. we can estimate the median usin af. graph. 3 I 3 16 +3=19 19+ 20 median the value where 50%. of data are below and 50%. of data are above
000000 D camulative frequency Age No students (F) Class with THI Freq. density cumulative fr O O 20 cumulative Frequency NO NOVO 970 2 10- JUENOTNOS 15 150 15.5 ≤ac16 sa 216.5 ≤94 17.549418.5 2 15.5 2= xx16 X=0.125 O.S ५ 2 6 for first class cumulative frequency is the same as frequency the last class cum. frequecicy must be equal to the total no. umulative frequency is a total number of students below. the upper boundary M=16+X M=16.125 MAGINOTIUNO.S 0.5 12 8 2+6-8,98+8 16 PINNINO IN how peo WOON M VONNSYA SNE O 16 17.5 14 DISTRIBUTION 16 16.5 when we connect each point with a straight segment we get a polygon. 18.5 cf never decreases nighest point is the total no. we can estimate the median usin af. graph. 3 I 3 16 +3=19 19+ 20 median the value where 50%. of data are below and 50%. of data are above
iOS User
Stefan S, iOS User
SuSSan, iOS User