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Section 4.1 Exponential Functions f(x)= a.b* is an exponential function with base b. If bal we have exponential growth. b is the growth factor, b-1 is the growth rate.. Ex. f(x) = 51.1 growth rate is 1.1-1=0.1 or 10% If 0<b<1 we have exponential decay. b is the decay factor, 1-b is the decay rate. Lab X Ex. 3.0.7 decay rate is 1-0.7= 0.3 or 30%EN, DONDOOMOD 10% COUNTING? Ex Linear: Exponential: XO1 2 3 у 5 10 20 чо Ex. A city has 75,000 people now and grows at a rate of 3% per year. P(t)=a.b₁ AASTING X 5 10 15 20 y 1 2 3 4 what is the exponential growth factor ? b = 1+0.03= 1.03₁ P(t) = 75 000 1.03 what will the population be in 8 years? t=8, P (8) = 75 000 1.03 = 95 008 . Ex. A car depreciates in value at a rate of 10% per year. If it's worth $19000 now how much will it be worth in 5 years? A = a·b b=1-0.1=0.9₁ A (t) = 190005 = $11,219.31 bo Ex. Find an exponential function y=a.b* that passes through: Wa=a= a)(0,7) and (2,63) b)(0,8) and (3,1) x,y 19 La y=8-b²² 3 1 = 8.6 (²)³ = (6³) ³ 1/1/2=b y-int is a y = 7.6* 2 63= 7.6² √a = √b² 3=b y = 7.3* y = 8 ( ²2 ) * Ex. A radioactive substance weighs 250 mg (0,250) now and will weigh 125 mg in...
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Stefan S, iOS User
SuSSan, iOS User
10 hours 10, 125). How much will be left in 16 hours ? 10 y = 250-0.93316 y =82.42 mg 423000 = 410000.6³ (1.0137) = (b) 1.0105=b 125 = 250. ·b" (b¹0) Fo To 0.5 = 0.933 = b Ex. A house is worth $410,000 now and is projected to be worth 423,000 in 3 years. years? what will it be worth in 10 = 410 000 b y = 410 000 1.015¹0 y $475,821.74 : . Section 4.1 Exponential Functions: Part 2/continued P=a·b & growth factor growth factoranox SECON Cinitial valuesult 2: 1-3 dat die lands A = a·b ²₁ decoy factor decay factor manbaks skad Linitial values act or del od wd Formulas for compound intrest: 20=ro-1 al sito int FV = P ( 1 + 1 )h² n FV = future value P = present value r= intrest value n = # of compoundings per year years t = # of FV=Pe' e≈ 2.71828 X 85 E المنسية was bol to store to suloy ni Ratoban continuous compounding the all of wow on then rt S J to eWORLD ANG Wom sigusa 100 c itwong whithamlogko 800 2PF 101.000 2K # hads "dad de prodhad hindrana 48
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Maria Hernandez
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Exponential growth and decay word problems and formulas.
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This is a complete notes of differential equations with applications.
Section 4.1 Exponential Functions f(x)= a.b* is an exponential function with base b. If bal we have exponential growth. b is the growth factor, b-1 is the growth rate.. Ex. f(x) = 51.1 growth rate is 1.1-1=0.1 or 10% If 0<b<1 we have exponential decay. b is the decay factor, 1-b is the decay rate. Lab X Ex. 3.0.7 decay rate is 1-0.7= 0.3 or 30%EN, DONDOOMOD 10% COUNTING? Ex Linear: Exponential: XO1 2 3 у 5 10 20 чо Ex. A city has 75,000 people now and grows at a rate of 3% per year. P(t)=a.b₁ AASTING X 5 10 15 20 y 1 2 3 4 what is the exponential growth factor ? b = 1+0.03= 1.03₁ P(t) = 75 000 1.03 what will the population be in 8 years? t=8, P (8) = 75 000 1.03 = 95 008 . Ex. A car depreciates in value at a rate of 10% per year. If it's worth $19000 now how much will it be worth in 5 years? A = a·b b=1-0.1=0.9₁ A (t) = 190005 = $11,219.31 bo Ex. Find an exponential function y=a.b* that passes through: Wa=a= a)(0,7) and (2,63) b)(0,8) and (3,1) x,y 19 La y=8-b²² 3 1 = 8.6 (²)³ = (6³) ³ 1/1/2=b y-int is a y = 7.6* 2 63= 7.6² √a = √b² 3=b y = 7.3* y = 8 ( ²2 ) * Ex. A radioactive substance weighs 250 mg (0,250) now and will weigh 125 mg in...
Section 4.1 Exponential Functions f(x)= a.b* is an exponential function with base b. If bal we have exponential growth. b is the growth factor, b-1 is the growth rate.. Ex. f(x) = 51.1 growth rate is 1.1-1=0.1 or 10% If 0<b<1 we have exponential decay. b is the decay factor, 1-b is the decay rate. Lab X Ex. 3.0.7 decay rate is 1-0.7= 0.3 or 30%EN, DONDOOMOD 10% COUNTING? Ex Linear: Exponential: XO1 2 3 у 5 10 20 чо Ex. A city has 75,000 people now and grows at a rate of 3% per year. P(t)=a.b₁ AASTING X 5 10 15 20 y 1 2 3 4 what is the exponential growth factor ? b = 1+0.03= 1.03₁ P(t) = 75 000 1.03 what will the population be in 8 years? t=8, P (8) = 75 000 1.03 = 95 008 . Ex. A car depreciates in value at a rate of 10% per year. If it's worth $19000 now how much will it be worth in 5 years? A = a·b b=1-0.1=0.9₁ A (t) = 190005 = $11,219.31 bo Ex. Find an exponential function y=a.b* that passes through: Wa=a= a)(0,7) and (2,63) b)(0,8) and (3,1) x,y 19 La y=8-b²² 3 1 = 8.6 (²)³ = (6³) ³ 1/1/2=b y-int is a y = 7.6* 2 63= 7.6² √a = √b² 3=b y = 7.3* y = 8 ( ²2 ) * Ex. A radioactive substance weighs 250 mg (0,250) now and will weigh 125 mg in...
iOS User
Stefan S, iOS User
SuSSan, iOS User
10 hours 10, 125). How much will be left in 16 hours ? 10 y = 250-0.93316 y =82.42 mg 423000 = 410000.6³ (1.0137) = (b) 1.0105=b 125 = 250. ·b" (b¹0) Fo To 0.5 = 0.933 = b Ex. A house is worth $410,000 now and is projected to be worth 423,000 in 3 years. years? what will it be worth in 10 = 410 000 b y = 410 000 1.015¹0 y $475,821.74 : . Section 4.1 Exponential Functions: Part 2/continued P=a·b & growth factor growth factoranox SECON Cinitial valuesult 2: 1-3 dat die lands A = a·b ²₁ decoy factor decay factor manbaks skad Linitial values act or del od wd Formulas for compound intrest: 20=ro-1 al sito int FV = P ( 1 + 1 )h² n FV = future value P = present value r= intrest value n = # of compoundings per year years t = # of FV=Pe' e≈ 2.71828 X 85 E المنسية was bol to store to suloy ni Ratoban continuous compounding the all of wow on then rt S J to eWORLD ANG Wom sigusa 100 c itwong whithamlogko 800 2PF 101.000 2K # hads "dad de prodhad hindrana 48