Algebra 223 views·Updated Aug 19, 2026·2 pages

Understanding the Sum and Difference of Cubes

Chelsea@zuncho

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Factoring polynomial expressions is like solving math puzzles that reveal...

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Sum and Difference of Cubes

Ever wondered how to break down complex cubic expressions? The key is memorizing two powerful formulas. For the difference of cubes, use: $a^3 - b^3 = (a - b)(a^2 + ab + b^2)$

For the sum of cubes, the pattern is slightly different: $a^3 + b^3 = (a + b)(a^2 - ab + b^2)$

Let's see this in action! When factoring $x^3 - 27$ , identify it as $x^3 - 3^3$ . Using the difference of cubes formula, this becomes $(x-3)(x^2+3x+9)$ . The first factor is simple, while the second never factors further.

💡 Quick Tip: When factoring expressions like $64a^6 - b^6$ , you can either factor as a difference of cubes first or as a difference of squares. Both approaches work, but choosing wisely can save you time!

Remember that sometimes you'll need to factor out common terms first. For example, with $2a^4 + 16a$ , first factor out $2a$ to get $2a(a^3+8)$ . Then the expression inside parentheses is a sum of cubes that factors as $2a(a+2)(a^2-2a+4)$ .

of 2

Factoring by Grouping Terms

Factoring by grouping is like solving a puzzle by rearranging pieces. This technique is super useful when expressions don't immediately look like standard patterns.

Start by looking for ways to rewrite the expression as a difference of squares $(a+b)(a-b)$ or as a perfect square minus another term. For example, with $x^2+6x+9-y^2$ , recognize that the first three terms form a perfect square trinomial: $(x+3)^2-y^2$ . This becomes $(x+3+y)(x+3-y)$ .

Sometimes you'll need to rearrange terms to spot the pattern. For expression $81-x^2+2xy-y^2$ , group the last three terms: $81-(x^2-2xy+y^2)$ , which simplifies to $81-(x-y)^2$ . This is a difference of squares that factors as $(9+x-y)(9-x+y)$ .

🔍 Strategy Alert: When factoring expressions with four terms, try grouping them into pairs. For example, in $7a^2x-6a^2-7x+6$ , group terms with common factors to get $a^2(7x-6)-1(7x-6)$ , which equals $(a^2-1)(7x-6)$ .

For trickier expressions like $49y^2-x^2-10x-25$ , recognize that the last three terms form $(x+5)^2$ with a negative sign. Rearranging gives $49y^2-(x+5)^2$ , which factors as $(7y+x+5)(7y-x-5)$ .

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Algebra 223 views·Updated Aug 19, 2026·2 pages

Understanding the Sum and Difference of Cubes

Chelsea@zuncho

Add to Google sources

Factoring polynomial expressions is like solving math puzzles that reveal hidden patterns. This guide will help you master factoring the sum and difference of cubes, along with related factoring techniques that make algebra problems much easier to solve.

of 2

Sum and Difference of Cubes

Ever wondered how to break down complex cubic expressions? The key is memorizing two powerful formulas. For the difference of cubes, use: $a^3 - b^3 = (a - b)(a^2 + ab + b^2)$

For the sum of cubes, the pattern is slightly different: $a^3 + b^3 = (a + b)(a^2 - ab + b^2)$

💡 Quick Tip: When factoring expressions like $64a^6 - b^6$ , you can either factor as a difference of cubes first or as a difference of squares. Both approaches work, but choosing wisely can save you time!

of 2

Factoring by Grouping Terms

Factoring by grouping is like solving a puzzle by rearranging pieces. This technique is super useful when expressions don't immediately look like standard patterns.

🔍 Strategy Alert: When factoring expressions with four terms, try grouping them into pairs. For example, in $7a^2x-6a^2-7x+6$ , group terms with common factors to get $a^2(7x-6)-1(7x-6)$ , which equals $(a^2-1)(7x-6)$ .

For trickier expressions like $49y^2-x^2-10x-25$ , recognize that the last three terms form $(x+5)^2$ with a negative sign. Rearranging gives $49y^2-(x+5)^2$ , which factors as $(7y+x+5)(7y-x-5)$ .

We thought you’d never ask...

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Sum and Difference of Cubes

Factoring by Grouping Terms

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