This compound has an empirical formula of C₃H₆O₂ and a molecular formula of C₆H₁₂O₄. The empirical formula represents the simplest whole number ratio of atoms in a compound, while the molecular formula shows the actual number of atoms of each element in a molecule.
Definition: An empirical formula gives the proportions of elements in a compound, while a molecular formula shows the actual number of atoms of each element in a molecule.
To find the empirical formula:
- Convert percentages to grams, assuming 100g of the compound.
- Calculate the number of moles for each element.
- Divide each mole value by the smallest number of moles.
- Round up or multiply to get whole numbers for the subscripts.
Example: For a compound with 48.64% Carbon, 8.16% Hydrogen, and 43.2% Oxygen:
- Convert to grams: 48.64g C, 8.16g H, 43.2g O
- Calculate moles: 4.05 mol C, 8.08 mol H, 2.7 mol O
- Divide by smallest (2.7): 1.5 C, 3 H, 1 O
- Multiply by 2 to get whole numbers: 3 C, 6 H, 2 O
Therefore, the empirical formula is C₃H₆O₂.
Highlight: To find the molecular formula from the empirical formula, you may need to multiply all subscripts by a common factor.
In this case, multiplying the empirical formula by 2 gives the molecular formula C₆H₁₂O₄.
Vocabulary: Molar mass is the mass of one mole of a substance, expressed in grams per mole (g/mol).
This example demonstrates how to find empirical formula with percentages and how to find molecular formula from empirical formula, which are crucial skills in chemistry.