Implicit Differentiation Basics
When dealing with equations where y isn't isolated , we need implicit differentiation. Unlike explicit equations , implicit equations require special handling when taking derivatives.
The key difference appears when differentiating terms containing y. For these terms, we must apply the chain rule and multiply by dy/dx. For example, when differentiating y², we get 2y·(dy/dx) instead of just 2y.
To find dy/dx using implicit differentiation:
- Differentiate both sides of the equation with respect to x
- Add dy/dx whenever differentiating a term with y
- Gather all dy/dx terms on one side
- Solve for dy/dx by isolating it
💡 Think of dy/dx as a variable you're solving for. When you see y in the equation, remember that y depends on x, so you need the chain rule and must include dy/dx in your derivative.
For example, to find dy/dx for y² - 5x³ = 3y:
- Differentiate: 2y(dy/dx) - 15x² = 3(dy/dx)
- Gather dy/dx terms: 2y(dy/dx) - 3(dy/dx) = 15x²
- Factor out dy/dx: (dy/dx) = 15x²
- Solve: dy/dx = 15x²/





















