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BUBBLE T CALCULATIONS EXAMPLE 3. Consider an ideal mixture. OF acetonitrile (1) / nitro methane (2). at pressure. OF 70 kPq. and X1 = 0.6. Det ermijne, the. Y₁ and T. Given:. Read:. Join :. P= 10 kPa X! =D.U. P = XIPI + Xm Pn sat P- XIPSat = XR PR. SCH. X₂2 P₁ sat = p - Xip, sat Piz sat P₂ sat .X2 = in Pisat 4₁. and. T. tau ation sat .P-. XIP, sat .P₂ Sa+ •. consider in Ai- in α = 'A₁ - For T: In pisat Bi T+Ci (T+ (₁) Pisar Prsat. In α = ( A₁ - AR) T i Ci= In Pisait - Ai = Ai.- POL ·TICI Bi .In Pjsat .- Ai Ai-In P. Sar. Bi . As - In P, rat In Pisat : T+Ci Bi Tt Ci Gi ( [ Avi- 102 ce ] 81 T + Cl Let a = ran: if P P₂ sa+ X2 + XIX. = X2 =' In Prisat P₁ sar P₂ sat P2 sat= B₂ T + C2 -X1X P P₂ sat P XX1 + X2 Ean. (2) · Ean. D directly. because • Ealls 2. &.3.: we cannot SONe . For T P₁ rat is also a Function. OF T ・(nonlinear. problem). · Solve by iteration.: STEPS: Assume an arbitrary value OF T (°C) ℗ calculated using Ean 2 and then p₂sat using Equation using. Ean. Calculate. T. prom . Antoine's compare ass umed T in step and. calculated T in Step ass umed T # calculated I repeat iteration procedure. IF Let in α ·Prsat T = 75°C In α = (14.895-14.7513.) x = 1,9339 Teat Teaic (Al- An) .P XXL + X2 1₂ JOf = 44.8025 kPa TO, KPg ・(1.9330) (0.600) +0.40. Bi Al-in pisat. 3381. 10 14.751m. In (44.8425) Tcalc = 1.7288°C Teak .#. Tassumed. After T= 76.6771 C In p₁...
iOS User
Stefan S, iOS User
SuSSan, iOS User
sat = 14.9950 iter atsons: 10. ·41 ± 0:7441 BI Tt.Cl •P₁ sat = 86, 8140 KPG Y1 =' Xip, sat P Y₁=. (0.00) (86.8140) t B.2 T1 C₂. 3413.10 15°C 1.250.23 x Pછૂ ડલ is calculated so we const allts for species 2. 227. 600 Repeat Iteration 3 413.10 16.0711°C + 250.523 3331.7.0 75 +227.6 Procedure use. Ear. T= 76. 6771 ° C. Pjsat = 86. 8140. kpa P₂ sat = 44.7790 K.Pq. .X.= .0.60 .X2. = .0.40 YL = .0.7.441. 42 = 0.2559. CREATION. OF TXY PLOT EXAMPLE 4. P= 10 kPa.. plot Given a. mixture .OF. ace tonitrile a. Txy. dla gram.. Given : Read: Plot Join: P = 10 KPQ • For in pisat -T₁ sat Find Tisat and Insat using Antoine's equation In pisat Bj = Ai- .Tt ci + Ci Bi In Pisat - Ai ace to nitrile (1) the ixy diagram ・T₁ sat = 70.0611° C T.C. 10. 0011 89. 6200 Ai = @ 12°C .and save. For. XI 1.4₁ In pisat 3413.10 14.8950-In (70 kPa). plot. Txy diagram, set values Bi TrCi 14.8950.- XL = 0.87 46 XI P₁ sat = 74. un 67 KPQ 250:5123 8419-10 12 + 250.523. P=⋅ X₁. (P₁SCH. Pasat). t. Pasat X1= P- Pesat Pisa Pasc Ean. For. I, sat. (1) OF T and For nitro methane (2) .33.31..70 to sat 14.1513 -In (70kPa) Tosat 89.4200 °C as TRSCH ≤ T ≤ T₁ sat In. Pesat nitro me thane (₂) CH то кра- эт. 143,2 кру 14.6267 kPa-.37.7432XPG. ·=· 14: 75-13 = Pasat = 37.7432 kPa - y₁= -2127 200 y₁ = 0.9324 . 3331,70 X₁ pisat P Y₁= (0.8740) (14.4747) TU KPg -12 22.1.6. PEW T CALCULATIONS EXAMPLE 3: Given a mixture OF acetonitrile (1) and T. and. XI. at P=.10.KPO and y₁=determine Given : P.= 10 кра y1 = 0.00 Read: T.&.XI. Sofil: Dew T. calculation .Yip = xi pisat xis Hip. Pisat Binary system.: .X1 + X1₂ = 1 Y.IP Pisat P( P.(!! VI Disat Pisar. PC VID, San Pisat угр Po sat t Tcale = Pisat B₂2 sat ·Teak = yż Psat ५२ P₂ Sar P(y₁ + y₂ x) = P₁ sat psat = P(y! + y2 a) sample. Iteration O Let T = 15 °C (2. In x= ⋅ (A₁- AR). + x = 1.93 39. (5) P₁ sat = P (Y₁+ 42 x) •T calc 79.9122 1 Y2 Pisar P₂ sat =1 Proce dure. 17 = pisat in α= (14.8950 - 14. 75 15 ) = 3413.10 75 + 250.123 BI Tr.Ci Ean. 4 Pisat = 10 kPa 60.600 + 0.40. (1..9339).) P₁ sat = 96. 1485 KPC. . Al-In pisat. ·3419..10. 148930-111(96-1485) tan. 4. .BR. TTCR -1250 Iteration Procedure: Ass ume an arbitrary value of. T.(°C). 2 calculate a using E an. Ⓒ and then Pisat using ean. Ⓒ nitromethane. (n) calculate. I from Ean using ean 3 compare. and 5 IF. ass umed . т.. repech the 3331.70. ·79 +227:6 5 . Arito ine's. ass umed I in step calculated t. in step I & calculated iteration. Comp are as sumed 1 vs Tcalc 15 °C. . 19. 9/12: C. .Repeat iteration. After iterations T= 19.135 °C For Pisat In P₁ salt = Ai - Solve in Pisat = 14. 8.950 Pisat = 25.01TR KPO SONe For Pq sat In Pesat = 14.7513- Prisat = Solve A1 = . - T1. Cl ча. 993 г кра For XI ∙Pi-Prsat P,SCH_ Pasat X₁ = 0.43 92 X₂ = 0: 5607 3413:10 79.735 + 250.523 3331. 10 ·79:735 +227 6000° то кра- ца. яз 32 кра 95.6172 KPQ- 49.9392 XPq
This note has solved examples in getting the bubble temperature and dew temperature in solution thermodynamics.
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Unit 12 of Chemistry Honors (Inorganic)
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Unit 4 chemistry notes (grade 10) intro to gases
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This note showcases four different gas laws used in chemistry, Boyle’s, Charle’s, Lussac’s, and even the combined gas law. there is a step-by-step example on how to evaluate a Combied Gas law.
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BUBBLE T CALCULATIONS EXAMPLE 3. Consider an ideal mixture. OF acetonitrile (1) / nitro methane (2). at pressure. OF 70 kPq. and X1 = 0.6. Det ermijne, the. Y₁ and T. Given:. Read:. Join :. P= 10 kPa X! =D.U. P = XIPI + Xm Pn sat P- XIPSat = XR PR. SCH. X₂2 P₁ sat = p - Xip, sat Piz sat P₂ sat .X2 = in Pisat 4₁. and. T. tau ation sat .P-. XIP, sat .P₂ Sa+ •. consider in Ai- in α = 'A₁ - For T: In pisat Bi T+Ci (T+ (₁) Pisar Prsat. In α = ( A₁ - AR) T i Ci= In Pisait - Ai = Ai.- POL ·TICI Bi .In Pjsat .- Ai Ai-In P. Sar. Bi . As - In P, rat In Pisat : T+Ci Bi Tt Ci Gi ( [ Avi- 102 ce ] 81 T + Cl Let a = ran: if P P₂ sa+ X2 + XIX. = X2 =' In Prisat P₁ sar P₂ sat P2 sat= B₂ T + C2 -X1X P P₂ sat P XX1 + X2 Ean. (2) · Ean. D directly. because • Ealls 2. &.3.: we cannot SONe . For T P₁ rat is also a Function. OF T ・(nonlinear. problem). · Solve by iteration.: STEPS: Assume an arbitrary value OF T (°C) ℗ calculated using Ean 2 and then p₂sat using Equation using. Ean. Calculate. T. prom . Antoine's compare ass umed T in step and. calculated T in Step ass umed T # calculated I repeat iteration procedure. IF Let in α ·Prsat T = 75°C In α = (14.895-14.7513.) x = 1,9339 Teat Teaic (Al- An) .P XXL + X2 1₂ JOf = 44.8025 kPa TO, KPg ・(1.9330) (0.600) +0.40. Bi Al-in pisat. 3381. 10 14.751m. In (44.8425) Tcalc = 1.7288°C Teak .#. Tassumed. After T= 76.6771 C In p₁...
BUBBLE T CALCULATIONS EXAMPLE 3. Consider an ideal mixture. OF acetonitrile (1) / nitro methane (2). at pressure. OF 70 kPq. and X1 = 0.6. Det ermijne, the. Y₁ and T. Given:. Read:. Join :. P= 10 kPa X! =D.U. P = XIPI + Xm Pn sat P- XIPSat = XR PR. SCH. X₂2 P₁ sat = p - Xip, sat Piz sat P₂ sat .X2 = in Pisat 4₁. and. T. tau ation sat .P-. XIP, sat .P₂ Sa+ •. consider in Ai- in α = 'A₁ - For T: In pisat Bi T+Ci (T+ (₁) Pisar Prsat. In α = ( A₁ - AR) T i Ci= In Pisait - Ai = Ai.- POL ·TICI Bi .In Pjsat .- Ai Ai-In P. Sar. Bi . As - In P, rat In Pisat : T+Ci Bi Tt Ci Gi ( [ Avi- 102 ce ] 81 T + Cl Let a = ran: if P P₂ sa+ X2 + XIX. = X2 =' In Prisat P₁ sar P₂ sat P2 sat= B₂ T + C2 -X1X P P₂ sat P XX1 + X2 Ean. (2) · Ean. D directly. because • Ealls 2. &.3.: we cannot SONe . For T P₁ rat is also a Function. OF T ・(nonlinear. problem). · Solve by iteration.: STEPS: Assume an arbitrary value OF T (°C) ℗ calculated using Ean 2 and then p₂sat using Equation using. Ean. Calculate. T. prom . Antoine's compare ass umed T in step and. calculated T in Step ass umed T # calculated I repeat iteration procedure. IF Let in α ·Prsat T = 75°C In α = (14.895-14.7513.) x = 1,9339 Teat Teaic (Al- An) .P XXL + X2 1₂ JOf = 44.8025 kPa TO, KPg ・(1.9330) (0.600) +0.40. Bi Al-in pisat. 3381. 10 14.751m. In (44.8425) Tcalc = 1.7288°C Teak .#. Tassumed. After T= 76.6771 C In p₁...
iOS User
Stefan S, iOS User
SuSSan, iOS User
sat = 14.9950 iter atsons: 10. ·41 ± 0:7441 BI Tt.Cl •P₁ sat = 86, 8140 KPG Y1 =' Xip, sat P Y₁=. (0.00) (86.8140) t B.2 T1 C₂. 3413.10 15°C 1.250.23 x Pછૂ ડલ is calculated so we const allts for species 2. 227. 600 Repeat Iteration 3 413.10 16.0711°C + 250.523 3331.7.0 75 +227.6 Procedure use. Ear. T= 76. 6771 ° C. Pjsat = 86. 8140. kpa P₂ sat = 44.7790 K.Pq. .X.= .0.60 .X2. = .0.40 YL = .0.7.441. 42 = 0.2559. CREATION. OF TXY PLOT EXAMPLE 4. P= 10 kPa.. plot Given a. mixture .OF. ace tonitrile a. Txy. dla gram.. Given : Read: Plot Join: P = 10 KPQ • For in pisat -T₁ sat Find Tisat and Insat using Antoine's equation In pisat Bj = Ai- .Tt ci + Ci Bi In Pisat - Ai ace to nitrile (1) the ixy diagram ・T₁ sat = 70.0611° C T.C. 10. 0011 89. 6200 Ai = @ 12°C .and save. For. XI 1.4₁ In pisat 3413.10 14.8950-In (70 kPa). plot. Txy diagram, set values Bi TrCi 14.8950.- XL = 0.87 46 XI P₁ sat = 74. un 67 KPQ 250:5123 8419-10 12 + 250.523. P=⋅ X₁. (P₁SCH. Pasat). t. Pasat X1= P- Pesat Pisa Pasc Ean. For. I, sat. (1) OF T and For nitro methane (2) .33.31..70 to sat 14.1513 -In (70kPa) Tosat 89.4200 °C as TRSCH ≤ T ≤ T₁ sat In. Pesat nitro me thane (₂) CH то кра- эт. 143,2 кру 14.6267 kPa-.37.7432XPG. ·=· 14: 75-13 = Pasat = 37.7432 kPa - y₁= -2127 200 y₁ = 0.9324 . 3331,70 X₁ pisat P Y₁= (0.8740) (14.4747) TU KPg -12 22.1.6. PEW T CALCULATIONS EXAMPLE 3: Given a mixture OF acetonitrile (1) and T. and. XI. at P=.10.KPO and y₁=determine Given : P.= 10 кра y1 = 0.00 Read: T.&.XI. Sofil: Dew T. calculation .Yip = xi pisat xis Hip. Pisat Binary system.: .X1 + X1₂ = 1 Y.IP Pisat P( P.(!! VI Disat Pisar. PC VID, San Pisat угр Po sat t Tcale = Pisat B₂2 sat ·Teak = yż Psat ५२ P₂ Sar P(y₁ + y₂ x) = P₁ sat psat = P(y! + y2 a) sample. Iteration O Let T = 15 °C (2. In x= ⋅ (A₁- AR). + x = 1.93 39. (5) P₁ sat = P (Y₁+ 42 x) •T calc 79.9122 1 Y2 Pisar P₂ sat =1 Proce dure. 17 = pisat in α= (14.8950 - 14. 75 15 ) = 3413.10 75 + 250.123 BI Tr.Ci Ean. 4 Pisat = 10 kPa 60.600 + 0.40. (1..9339).) P₁ sat = 96. 1485 KPC. . Al-In pisat. ·3419..10. 148930-111(96-1485) tan. 4. .BR. TTCR -1250 Iteration Procedure: Ass ume an arbitrary value of. T.(°C). 2 calculate a using E an. Ⓒ and then Pisat using ean. Ⓒ nitromethane. (n) calculate. I from Ean using ean 3 compare. and 5 IF. ass umed . т.. repech the 3331.70. ·79 +227:6 5 . Arito ine's. ass umed I in step calculated t. in step I & calculated iteration. Comp are as sumed 1 vs Tcalc 15 °C. . 19. 9/12: C. .Repeat iteration. After iterations T= 19.135 °C For Pisat In P₁ salt = Ai - Solve in Pisat = 14. 8.950 Pisat = 25.01TR KPO SONe For Pq sat In Pesat = 14.7513- Prisat = Solve A1 = . - T1. Cl ча. 993 г кра For XI ∙Pi-Prsat P,SCH_ Pasat X₁ = 0.43 92 X₂ = 0: 5607 3413:10 79.735 + 250.523 3331. 10 ·79:735 +227 6000° то кра- ца. яз 32 кра 95.6172 KPQ- 49.9392 XPq