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1 40 40 D Ⓒ O O thagorean Theorem Geometry Notes explains relationship between the 3 sides of a triangle Formula C = √√√9² +6² 9² + b² = C² axa + bxb = Gxc a altitude bi base c: hypotenuse example side I altitude side 3 hypotenuse Side 2 base 1 5 h find the hypotenuse: 6 ? 9²+ b² = c² 7x7=419 + 6x6 =36 = 6² √85=√C²k 9.21 round 2 find side bi 9² + b² = c² 5²+6²=7² 7 25+ b² = 49 -25 -25 ↑ get rid of (2) decimal places √₁6³² = √24 = 4.89 decimal round z places ? 5 D h 3 get rid of find side a 9² + b² = c² 2 9² +3²= 5² 9² +91=25 -9-9 √a² =√16 = 141 9² + g = 2 2 9 $ } 9=3 O Pythagorean Theorem "Continued" Right angle Obtuse triangle and Acute triangle. h right triangle • Fortula & c²= a² + b² examples: C = 5 b = 4 C² = 25 9² + b ² 9 + 16 = 25 -right= | +60 both equal to 25 a=3 triangle 11443 obtuse triangle Formula: C²>q² tb² 0 = 6 b=4 62=36 9² +6² 9+16=25 Acute Triangle Formula C² <a² + b² 9=3 Cis greater than a²+ b² обтите triangle b=3 C = 4 19²+ b² C = 16 bis greater 9² +6² √² than 9+9=1872 -acute triangle
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Stefan S, iOS User
SuSSan, iOS User
Notes
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Unit 7 Study Guide 50.52.53 Solutions
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Unit 7 Study Guide pages 50.51.53.54 Solutions
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Study guide for all things circle
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1 40 40 D Ⓒ O O thagorean Theorem Geometry Notes explains relationship between the 3 sides of a triangle Formula C = √√√9² +6² 9² + b² = C² axa + bxb = Gxc a altitude bi base c: hypotenuse example side I altitude side 3 hypotenuse Side 2 base 1 5 h find the hypotenuse: 6 ? 9²+ b² = c² 7x7=419 + 6x6 =36 = 6² √85=√C²k 9.21 round 2 find side bi 9² + b² = c² 5²+6²=7² 7 25+ b² = 49 -25 -25 ↑ get rid of (2) decimal places √₁6³² = √24 = 4.89 decimal round z places ? 5 D h 3 get rid of find side a 9² + b² = c² 2 9² +3²= 5² 9² +91=25 -9-9 √a² =√16 = 141 9² + g = 2 2 9 $ } 9=3 O Pythagorean Theorem "Continued" Right angle Obtuse triangle and Acute triangle. h right triangle • Fortula & c²= a² + b² examples: C = 5 b = 4 C² = 25 9² + b ² 9 + 16 = 25 -right= | +60 both equal to 25 a=3 triangle 11443 obtuse triangle Formula: C²>q² tb² 0 = 6 b=4 62=36 9² +6² 9+16=25 Acute Triangle Formula C² <a² + b² 9=3 Cis greater than a²+ b² обтите triangle b=3 C = 4 19²+ b² C = 16 bis greater 9² +6² √² than 9+9=1872 -acute triangle
1 40 40 D Ⓒ O O thagorean Theorem Geometry Notes explains relationship between the 3 sides of a triangle Formula C = √√√9² +6² 9² + b² = C² axa + bxb = Gxc a altitude bi base c: hypotenuse example side I altitude side 3 hypotenuse Side 2 base 1 5 h find the hypotenuse: 6 ? 9²+ b² = c² 7x7=419 + 6x6 =36 = 6² √85=√C²k 9.21 round 2 find side bi 9² + b² = c² 5²+6²=7² 7 25+ b² = 49 -25 -25 ↑ get rid of (2) decimal places √₁6³² = √24 = 4.89 decimal round z places ? 5 D h 3 get rid of find side a 9² + b² = c² 2 9² +3²= 5² 9² +91=25 -9-9 √a² =√16 = 141 9² + g = 2 2 9 $ } 9=3 O Pythagorean Theorem "Continued" Right angle Obtuse triangle and Acute triangle. h right triangle • Fortula & c²= a² + b² examples: C = 5 b = 4 C² = 25 9² + b ² 9 + 16 = 25 -right= | +60 both equal to 25 a=3 triangle 11443 obtuse triangle Formula: C²>q² tb² 0 = 6 b=4 62=36 9² +6² 9+16=25 Acute Triangle Formula C² <a² + b² 9=3 Cis greater than a²+ b² обтите triangle b=3 C = 4 19²+ b² C = 16 bis greater 9² +6² √² than 9+9=1872 -acute triangle
iOS User
Stefan S, iOS User
SuSSan, iOS User