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Comprehensive Chapter 9 Notes on Fluids, Density, and Buoyancy for AP Physics 2

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E

Elizabeth Gabante

11/27/2025

Physics

Chapter 9 Notes Fluids, density, and buoyancy

82

Nov 27, 2025

9 pages

Comprehensive Chapter 9 Notes on Fluids, Density, and Buoyancy for AP Physics 2

E

Elizabeth Gabante

@elizabethgabante_mpdt

Let's dive into the fascinating world of fluids! This chapter... Show more

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# Chapter nine: Fluids

Density and Pressure

DENSITY IS DEFINED AS

$\rho$=$\frac{m}{V}$kg/m³

PRESSURE IS DEFINED AS

P=$\,\frac{F}{A}$Pa

Density and Pressure

Ever wonder why some objects float while others sink? It all comes down to density. Density is calculated as mass divided by volume ρ=m/Vρ = m/V and is measured in kg/m³. The higher the density, the more mass is packed into a given space.

Pressure is another key concept, defined as force divided by area P=F/AP = F/A and measured in pascals (Pa). When you stand on ice with regular shoes versus ice skates, you apply the same force but different pressures because of the different contact areas.

Specific gravity tells us how an object's density compares to water's density. If specific gravity is less than 1, the object floats (like wood). If it's greater than 1, the object sinks (like a rock). Objects with specific gravity equal to 1 will be neutrally buoyant, hovering in the water.

Think about it: Why does a massive steel ship float while a small steel nail sinks? The answer lies in the average density of the ship (including the air inside) compared to water!

# Chapter nine: Fluids

Density and Pressure

DENSITY IS DEFINED AS

$\rho$=$\frac{m}{V}$kg/m³

PRESSURE IS DEFINED AS

P=$\,\frac{F}{A}$Pa

Fluid Pressure and Depth

The deeper you go in a fluid, the more pressure you feel. This relationship is described by the formula P = P₀ + ρgh, where P₀ is the pressure at the surface, ρ is the fluid's density, g is gravity, and h is depth.

When you're swimming, the pressure on your ears increases as you dive deeper. This happens because the weight of water above you increases with depth. Two objects at the same depth in a fluid experience equal pressure, but the top and bottom of an object feel different pressures because they're at different depths.

For objects in fluids, we can analyze the forces acting on them. The pressure forces on the sides of an object cancel out (since they're at the same depth), but the bottom face experiences greater pressure than the top face. This pressure difference creates the buoyant force.

When comparing two different fluids at the same pressure level, the relationship between density and height becomes clear: if one fluid column is taller than another, the shorter column must contain a denser fluid to create the same pressure.

# Chapter nine: Fluids

Density and Pressure

DENSITY IS DEFINED AS

$\rho$=$\frac{m}{V}$kg/m³

PRESSURE IS DEFINED AS

P=$\,\frac{F}{A}$Pa

Buoyant Force and Archimedes' Principle

When you drop an object in water, it feels lighter - that's the buoyant force at work! According to Archimedes' principle, any object submerged in a fluid experiences an upward buoyant force equal to the weight of the fluid it displaces.

For completely submerged objects, the buoyant force is F₁ = ρ₁V₁g, where ρ₁ is the fluid's density and V₁ is the volume of the object. This force competes with the object's weight F2=mgF₂ = mg. If the buoyant force exceeds the weight, the object rises; if weight wins, the object sinks.

For partially submerged objects (like a floating boat), we can determine what percentage will be submerged using a simple relationship: the percentage submerged equals the ratio of the object's density to the fluid's density. This explains why ice floats with about 90% of its volume underwater.

Quick tip: To determine if something will float, just compare its density to the fluid's density - no need for complex calculations!

# Chapter nine: Fluids

Density and Pressure

DENSITY IS DEFINED AS

$\rho$=$\frac{m}{V}$kg/m³

PRESSURE IS DEFINED AS

P=$\,\frac{F}{A}$Pa

Pascal's Principle and Hydraulics

Have you ever wondered how car jacks lift heavy vehicles with minimal effort? They use Pascal's principle, which states that pressure applied to an enclosed fluid is transmitted equally throughout the fluid and to container walls.

Hydraulic systems multiply force through different-sized pistons. In a hydraulic press, the pressure is the same throughout the system P1=P2P₁ = P₂, but the force is multiplied by the ratio of the areas: F₂/F₁ = A₂/A₁. This explains how a small force on a small piston can lift a car on a larger piston.

The trade-off is distance: while you gain force, you lose distance. The work done is the same on both ends W1=W2W₁ = W₂, meaning F₁Δx₁ = F₂Δx₂. So if the force is multiplied by 9, the distance moved is reduced by a factor of 9.

Working through an example problem: To lift a 13,300 N car with a hydraulic lift smallpistonradius=5cm,largepistonradius=15cmsmall piston radius = 5 cm, large piston radius = 15 cm, you need 1,480 N of force on the small piston, requiring a pressure of 1.88 × 10⁵ Pa.

# Chapter nine: Fluids

Density and Pressure

DENSITY IS DEFINED AS

$\rho$=$\frac{m}{V}$kg/m³

PRESSURE IS DEFINED AS

P=$\,\frac{F}{A}$Pa

Measuring Pressure and Practical Applications

Pressure plays a crucial role in our everyday lives, from weather forecasts to vehicle maintenance. We measure pressure using instruments like manometers (for enclosed fluids) and barometers (for atmospheric pressure).

When using a manometer, we distinguish between absolute pressure (total pressure P) and gauge pressure PP0,thedifferencefromatmosphericpressureP-P₀, the difference from atmospheric pressure. If the system's pressure exceeds atmospheric pressure, the height difference in the manometer is positive; if it's lower, the height is negative.

Let's see how buoyancy principles apply to real problems. For instance, when measuring a metal bracelet in air (0.100 N) and water (0.092 N), we can calculate its density. The buoyant force equals the weight difference (0.008 N), which equals ρ₁V₁g. Solving for the volume and using the weight measurement, we determine the metal density is approximately 12,500 kg/m³.

Application alert: This density measurement technique is used by jewelers to authenticate precious metals and gemstones!

# Chapter nine: Fluids

Density and Pressure

DENSITY IS DEFINED AS

$\rho$=$\frac{m}{V}$kg/m³

PRESSURE IS DEFINED AS

P=$\,\frac{F}{A}$Pa

Buoyancy in Action

Why do icebergs show only their "tips" above water? We can calculate exactly how much of an iceberg remains underwater using density principles. Given that ice has a density of 917 kg/m³ and salt water 1,025 kg/m³, we find that about 89.5% of an iceberg sits below the surface.

The calculation relies on the balance of forces: when an object floats, the buoyant force equals the weight force F1=F2F₁ = F₂. Using the formula ρ₁V₁g = ρₒVₒg and considering that only part of the volume is submerged, we get ρₒ/ρ₁ = h/H (where h is the submerged height and H is the total height).

It's important to understand that buoyant force depends only on the volume of fluid displaced and the fluid's density, not on the object's density. This means objects of different densities but identical volumes experience the same buoyant force in the same fluid.

If an object is denser than the fluid and rests on the container bottom, the normal force will be smaller than in air because the buoyant force supports part of the weight. This principle is why objects feel lighter underwater.

# Chapter nine: Fluids

Density and Pressure

DENSITY IS DEFINED AS

$\rho$=$\frac{m}{V}$kg/m³

PRESSURE IS DEFINED AS

P=$\,\frac{F}{A}$Pa

Fluid Flow: Laminar vs. Turbulent

When you watch water flow from a faucet, you might notice it flows smoothly at low speeds but becomes chaotic at higher speeds. Fluid flow can be classified as either streamline/laminar (smooth, predictable paths) or turbulent (irregular, chaotic motion).

Viscosity describes how resistant a fluid is to flow - water has low viscosity while maple syrup has high viscosity. When studying fluid dynamics, scientists often simplify by considering an "ideal fluid" that has no viscosity, is incompressible, moves steadily, and flows without turbulence.

A key principle in fluid dynamics is that the volume flow rate remains constant throughout a pipe system. This means that in areas where a pipe narrows, the fluid must speed up to maintain the same volume flow rate. This relationship is expressed by the continuity equation: A₁v₁ = A₂v₂.

Real-world example: Notice how water speeds up when you partially cover the end of a garden hose with your thumb? That's the continuity equation in action!

# Chapter nine: Fluids

Density and Pressure

DENSITY IS DEFINED AS

$\rho$=$\frac{m}{V}$kg/m³

PRESSURE IS DEFINED AS

P=$\,\frac{F}{A}$Pa

Bernoulli's Principle

Ever wonder how airplanes generate lift? It's all about Bernoulli's principle, which relates pressure, speed, and height in a moving fluid. The principle states that as a fluid's velocity increases, its pressure decreases.

Bernoulli's equation combines energy concepts: P₁ + ½ρv₁² + ρgy₁ = P₂ + ½ρv₂² + ρgy₂. Each term represents different energy types: pressure energy (P), kinetic energy (½ρv²), and potential energy (ρgy). For a given fluid, the sum of these energies remains constant along a streamline.

Deriving this equation involves analyzing work and energy. As fluid moves through a pipe, forces do work on the fluid. The net work equals the change in the fluid's kinetic and potential energy. After some algebra, we get Bernoulli's equation.

For horizontal flows where heights are equal, the equation simplifies to P₁ + ½ρv₁² = P₂ + ½ρv₂². This shows the inverse relationship between pressure and velocity - a principle that explains lift on airplane wings and how spray bottles work.

Fun fact: The spray mechanism in perfume bottles works because of Bernoulli's principle - squeezing the bulb forces air across the tube at high velocity, creating low pressure that draws liquid up!

# Chapter nine: Fluids

Density and Pressure

DENSITY IS DEFINED AS

$\rho$=$\frac{m}{V}$kg/m³

PRESSURE IS DEFINED AS

P=$\,\frac{F}{A}$Pa

Applications of Fluid Dynamics

Fluid dynamics principles show up in surprising places! The Venturi tube demonstrates Bernoulli's principle perfectly: when fluid flows through a constricted section, its velocity increases and its pressure decreases.

This pressure-velocity relationship explains why airplanes generate lift. Air moving over the curved upper surface of a wing travels faster than air underneath, creating lower pressure above the wing than below it. This pressure difference pushes the wing upward, creating lift.

When applying Bernoulli's equation, remember to establish your reference points carefully. For open containers, the pressure at the open surface equals atmospheric pressure. For height references, you can define your own "zero line" as long as you're consistent.

For practical applications, the equation can be simplified depending on the situation. If the heights are equal, the height terms cancel out. If both points are open to atmosphere, the pressure terms might cancel. In some cases, we can even remove density from both sides of the equation.

Engineering application: Engineers use these principles to design everything from carburetors in cars to blood pressure monitors in hospitals!



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The app is very easy to use and well designed. I have found everything I was looking for so far and have been able to learn a lot from the presentations! I will definitely use the app for a class assignment! And of course it also helps a lot as an inspiration.

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This app is really great. There are so many study notes and help [...]. My problem subject is French, for example, and the app has so many options for help. Thanks to this app, I have improved my French. I would recommend it to anyone.

Samantha Klich

Android user

Wow, I am really amazed. I just tried the app because I've seen it advertised many times and was absolutely stunned. This app is THE HELP you want for school and above all, it offers so many things, such as workouts and fact sheets, which have been VERY helpful to me personally.

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iOS user

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Brad T

Android user

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David K

iOS user

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Android user

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Greenlight Bonnie

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Physics

82

Nov 27, 2025

9 pages

Comprehensive Chapter 9 Notes on Fluids, Density, and Buoyancy for AP Physics 2

E

Elizabeth Gabante

@elizabethgabante_mpdt

Let's dive into the fascinating world of fluids! This chapter explores how liquids and gases behave, including concepts like density, pressure, buoyancy, and fluid motion. Understanding these principles helps explain everything from why boats float to how hydraulic systems work.

# Chapter nine: Fluids

Density and Pressure

DENSITY IS DEFINED AS

$\rho$=$\frac{m}{V}$kg/m³

PRESSURE IS DEFINED AS

P=$\,\frac{F}{A}$Pa

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Density and Pressure

Ever wonder why some objects float while others sink? It all comes down to density. Density is calculated as mass divided by volume ρ=m/Vρ = m/V and is measured in kg/m³. The higher the density, the more mass is packed into a given space.

Pressure is another key concept, defined as force divided by area P=F/AP = F/A and measured in pascals (Pa). When you stand on ice with regular shoes versus ice skates, you apply the same force but different pressures because of the different contact areas.

Specific gravity tells us how an object's density compares to water's density. If specific gravity is less than 1, the object floats (like wood). If it's greater than 1, the object sinks (like a rock). Objects with specific gravity equal to 1 will be neutrally buoyant, hovering in the water.

Think about it: Why does a massive steel ship float while a small steel nail sinks? The answer lies in the average density of the ship (including the air inside) compared to water!

# Chapter nine: Fluids

Density and Pressure

DENSITY IS DEFINED AS

$\rho$=$\frac{m}{V}$kg/m³

PRESSURE IS DEFINED AS

P=$\,\frac{F}{A}$Pa

Sign up to see the contentIt's free!

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Fluid Pressure and Depth

The deeper you go in a fluid, the more pressure you feel. This relationship is described by the formula P = P₀ + ρgh, where P₀ is the pressure at the surface, ρ is the fluid's density, g is gravity, and h is depth.

When you're swimming, the pressure on your ears increases as you dive deeper. This happens because the weight of water above you increases with depth. Two objects at the same depth in a fluid experience equal pressure, but the top and bottom of an object feel different pressures because they're at different depths.

For objects in fluids, we can analyze the forces acting on them. The pressure forces on the sides of an object cancel out (since they're at the same depth), but the bottom face experiences greater pressure than the top face. This pressure difference creates the buoyant force.

When comparing two different fluids at the same pressure level, the relationship between density and height becomes clear: if one fluid column is taller than another, the shorter column must contain a denser fluid to create the same pressure.

# Chapter nine: Fluids

Density and Pressure

DENSITY IS DEFINED AS

$\rho$=$\frac{m}{V}$kg/m³

PRESSURE IS DEFINED AS

P=$\,\frac{F}{A}$Pa

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Buoyant Force and Archimedes' Principle

When you drop an object in water, it feels lighter - that's the buoyant force at work! According to Archimedes' principle, any object submerged in a fluid experiences an upward buoyant force equal to the weight of the fluid it displaces.

For completely submerged objects, the buoyant force is F₁ = ρ₁V₁g, where ρ₁ is the fluid's density and V₁ is the volume of the object. This force competes with the object's weight F2=mgF₂ = mg. If the buoyant force exceeds the weight, the object rises; if weight wins, the object sinks.

For partially submerged objects (like a floating boat), we can determine what percentage will be submerged using a simple relationship: the percentage submerged equals the ratio of the object's density to the fluid's density. This explains why ice floats with about 90% of its volume underwater.

Quick tip: To determine if something will float, just compare its density to the fluid's density - no need for complex calculations!

# Chapter nine: Fluids

Density and Pressure

DENSITY IS DEFINED AS

$\rho$=$\frac{m}{V}$kg/m³

PRESSURE IS DEFINED AS

P=$\,\frac{F}{A}$Pa

Sign up to see the contentIt's free!

Access to all documents

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By signing up you accept Terms of Service and Privacy Policy

Pascal's Principle and Hydraulics

Have you ever wondered how car jacks lift heavy vehicles with minimal effort? They use Pascal's principle, which states that pressure applied to an enclosed fluid is transmitted equally throughout the fluid and to container walls.

Hydraulic systems multiply force through different-sized pistons. In a hydraulic press, the pressure is the same throughout the system P1=P2P₁ = P₂, but the force is multiplied by the ratio of the areas: F₂/F₁ = A₂/A₁. This explains how a small force on a small piston can lift a car on a larger piston.

The trade-off is distance: while you gain force, you lose distance. The work done is the same on both ends W1=W2W₁ = W₂, meaning F₁Δx₁ = F₂Δx₂. So if the force is multiplied by 9, the distance moved is reduced by a factor of 9.

Working through an example problem: To lift a 13,300 N car with a hydraulic lift smallpistonradius=5cm,largepistonradius=15cmsmall piston radius = 5 cm, large piston radius = 15 cm, you need 1,480 N of force on the small piston, requiring a pressure of 1.88 × 10⁵ Pa.

# Chapter nine: Fluids

Density and Pressure

DENSITY IS DEFINED AS

$\rho$=$\frac{m}{V}$kg/m³

PRESSURE IS DEFINED AS

P=$\,\frac{F}{A}$Pa

Sign up to see the contentIt's free!

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Measuring Pressure and Practical Applications

Pressure plays a crucial role in our everyday lives, from weather forecasts to vehicle maintenance. We measure pressure using instruments like manometers (for enclosed fluids) and barometers (for atmospheric pressure).

When using a manometer, we distinguish between absolute pressure (total pressure P) and gauge pressure PP0,thedifferencefromatmosphericpressureP-P₀, the difference from atmospheric pressure. If the system's pressure exceeds atmospheric pressure, the height difference in the manometer is positive; if it's lower, the height is negative.

Let's see how buoyancy principles apply to real problems. For instance, when measuring a metal bracelet in air (0.100 N) and water (0.092 N), we can calculate its density. The buoyant force equals the weight difference (0.008 N), which equals ρ₁V₁g. Solving for the volume and using the weight measurement, we determine the metal density is approximately 12,500 kg/m³.

Application alert: This density measurement technique is used by jewelers to authenticate precious metals and gemstones!

# Chapter nine: Fluids

Density and Pressure

DENSITY IS DEFINED AS

$\rho$=$\frac{m}{V}$kg/m³

PRESSURE IS DEFINED AS

P=$\,\frac{F}{A}$Pa

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Buoyancy in Action

Why do icebergs show only their "tips" above water? We can calculate exactly how much of an iceberg remains underwater using density principles. Given that ice has a density of 917 kg/m³ and salt water 1,025 kg/m³, we find that about 89.5% of an iceberg sits below the surface.

The calculation relies on the balance of forces: when an object floats, the buoyant force equals the weight force F1=F2F₁ = F₂. Using the formula ρ₁V₁g = ρₒVₒg and considering that only part of the volume is submerged, we get ρₒ/ρ₁ = h/H (where h is the submerged height and H is the total height).

It's important to understand that buoyant force depends only on the volume of fluid displaced and the fluid's density, not on the object's density. This means objects of different densities but identical volumes experience the same buoyant force in the same fluid.

If an object is denser than the fluid and rests on the container bottom, the normal force will be smaller than in air because the buoyant force supports part of the weight. This principle is why objects feel lighter underwater.

# Chapter nine: Fluids

Density and Pressure

DENSITY IS DEFINED AS

$\rho$=$\frac{m}{V}$kg/m³

PRESSURE IS DEFINED AS

P=$\,\frac{F}{A}$Pa

Sign up to see the contentIt's free!

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Fluid Flow: Laminar vs. Turbulent

When you watch water flow from a faucet, you might notice it flows smoothly at low speeds but becomes chaotic at higher speeds. Fluid flow can be classified as either streamline/laminar (smooth, predictable paths) or turbulent (irregular, chaotic motion).

Viscosity describes how resistant a fluid is to flow - water has low viscosity while maple syrup has high viscosity. When studying fluid dynamics, scientists often simplify by considering an "ideal fluid" that has no viscosity, is incompressible, moves steadily, and flows without turbulence.

A key principle in fluid dynamics is that the volume flow rate remains constant throughout a pipe system. This means that in areas where a pipe narrows, the fluid must speed up to maintain the same volume flow rate. This relationship is expressed by the continuity equation: A₁v₁ = A₂v₂.

Real-world example: Notice how water speeds up when you partially cover the end of a garden hose with your thumb? That's the continuity equation in action!

# Chapter nine: Fluids

Density and Pressure

DENSITY IS DEFINED AS

$\rho$=$\frac{m}{V}$kg/m³

PRESSURE IS DEFINED AS

P=$\,\frac{F}{A}$Pa

Sign up to see the contentIt's free!

Access to all documents

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Join milions of students

By signing up you accept Terms of Service and Privacy Policy

Bernoulli's Principle

Ever wonder how airplanes generate lift? It's all about Bernoulli's principle, which relates pressure, speed, and height in a moving fluid. The principle states that as a fluid's velocity increases, its pressure decreases.

Bernoulli's equation combines energy concepts: P₁ + ½ρv₁² + ρgy₁ = P₂ + ½ρv₂² + ρgy₂. Each term represents different energy types: pressure energy (P), kinetic energy (½ρv²), and potential energy (ρgy). For a given fluid, the sum of these energies remains constant along a streamline.

Deriving this equation involves analyzing work and energy. As fluid moves through a pipe, forces do work on the fluid. The net work equals the change in the fluid's kinetic and potential energy. After some algebra, we get Bernoulli's equation.

For horizontal flows where heights are equal, the equation simplifies to P₁ + ½ρv₁² = P₂ + ½ρv₂². This shows the inverse relationship between pressure and velocity - a principle that explains lift on airplane wings and how spray bottles work.

Fun fact: The spray mechanism in perfume bottles works because of Bernoulli's principle - squeezing the bulb forces air across the tube at high velocity, creating low pressure that draws liquid up!

# Chapter nine: Fluids

Density and Pressure

DENSITY IS DEFINED AS

$\rho$=$\frac{m}{V}$kg/m³

PRESSURE IS DEFINED AS

P=$\,\frac{F}{A}$Pa

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Applications of Fluid Dynamics

Fluid dynamics principles show up in surprising places! The Venturi tube demonstrates Bernoulli's principle perfectly: when fluid flows through a constricted section, its velocity increases and its pressure decreases.

This pressure-velocity relationship explains why airplanes generate lift. Air moving over the curved upper surface of a wing travels faster than air underneath, creating lower pressure above the wing than below it. This pressure difference pushes the wing upward, creating lift.

When applying Bernoulli's equation, remember to establish your reference points carefully. For open containers, the pressure at the open surface equals atmospheric pressure. For height references, you can define your own "zero line" as long as you're consistent.

For practical applications, the equation can be simplified depending on the situation. If the heights are equal, the height terms cancel out. If both points are open to atmosphere, the pressure terms might cancel. In some cases, we can even remove density from both sides of the equation.

Engineering application: Engineers use these principles to design everything from carburetors in cars to blood pressure monitors in hospitals!

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The app is very easy to use and well designed. I have found everything I was looking for so far and have been able to learn a lot from the presentations! I will definitely use the app for a class assignment! And of course it also helps a lot as an inspiration.

Stefan S

iOS user

This app is really great. There are so many study notes and help [...]. My problem subject is French, for example, and the app has so many options for help. Thanks to this app, I have improved my French. I would recommend it to anyone.

Samantha Klich

Android user

Wow, I am really amazed. I just tried the app because I've seen it advertised many times and was absolutely stunned. This app is THE HELP you want for school and above all, it offers so many things, such as workouts and fact sheets, which have been VERY helpful to me personally.

Anna

iOS user

I think it’s very much worth it and you’ll end up using it a lot once you get the hang of it and even after looking at others notes you can still ask your Artificial intelligence buddy the question and ask to simplify it if you still don’t get it!!! In the end I think it’s worth it 😊👍 ⚠️Also DID I MENTION ITS FREEE YOU DON’T HAVE TO PAY FOR ANYTHING AND STILL GET YOUR GRADES IN PERFECTLY❗️❗️⚠️

Thomas R

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Knowunity is the BEST app I’ve used in a minute. This is not an ai review or anything this is genuinely coming from a 7th grade student (I know 2011 im young) but dude this app is a 10/10 i have maintained a 3.8 gpa and have plenty of time for gaming. I love it and my mom is just happy I got good grades

Brad T

Android user

Not only did it help me find the answer but it also showed me alternative ways to solve it. I was horrible in math and science but now I have an a in both subjects. Thanks for the help🤍🤍

David K

iOS user

The app's just great! All I have to do is enter the topic in the search bar and I get the response real fast. I don't have to watch 10 YouTube videos to understand something, so I'm saving my time. Highly recommended!

Sudenaz Ocak

Android user

In school I was really bad at maths but thanks to the app, I am doing better now. I am so grateful that you made the app.

Greenlight Bonnie

Android user

I found this app a couple years ago and it has only gotten better since then. I really love it because it can help with written questions and photo questions. Also, it can find study guides that other people have made as well as flashcard sets and practice tests. The free version is also amazing for students who might not be able to afford it. Would 100% recommend

Aubrey

iOS user

Best app if you're in Highschool or Junior high. I have been using this app for 2 school years and it's the best, it's good if you don't have anyone to help you with school work.😋🩷🎀

Marco B

iOS user

THE QUIZES AND FLASHCARDS ARE SO USEFUL AND I LOVE THE SCHOOLGPT. IT ALSO IS LITREALLY LIKE CHATGPT BUT SMARTER!! HELPED ME WITH MY MASCARA PROBLEMS TOO!! AS WELL AS MY REAL SUBJECTS ! DUHHH 😍😁😲🤑💗✨🎀😮

Elisha

iOS user

This app is phenomenal down to the correct info and the various topics you can study! I greatly recommend it for people who struggle with procrastination and those who need homework help. It has been perfectly accurate for world 1 history as far as I’ve seen! Geometry too!

Paul T

iOS user