Chemistry130 views·Updated May 29, 2026·3 pages

General Chemistry 1: Quiz 7 Review

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Quantum mechanics is a fascinating branch of chemistry that helps... Show more

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$CHEM 2031 (Quiz 9) Name Student Number This quiz has two pages. $h=6.63 \times 10^{-34}$ J-s $1 nm = 10^{-9} m$ $R_H=2.18 \times 10^{-18}$ J$

Quantum Numbers and Electron Configuration Basics

Quantum numbers are essential values that describe the location and spin of electrons in atoms. The principal quantum number (n) determines the main energy level, while the angular quantum number (l) describes the subshell shape. For any given n, possible l values range from 0 to n-1.

When n = 1, only l = 0 is possible, representing the s orbital. For the 3d subshell, the possible magnetic quantum numbers (ml) are -2, -1, 0, 1, and 2, because d orbitals have l = 2 and ml ranges from -l to +l. The 3p subshell can hold up to 6 electrons because it contains three orbitals (3px, 3py, 3pz), each accommodating 2 electrons.

An electron with ml = 2 must be in an orbital with l ≥ 2, meaning the smallest possible principal quantum number would be n = 3. This demonstrates how quantum numbers are interconnected and follow specific rules.

💡 Think of quantum numbers as an electron's "address" in an atom - n is like the neighborhood, l is the street, ml is the house number, and ms is the specific room!

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$CHEM 2031 (Quiz 9) Name Student Number This quiz has two pages. $h=6.63 \times 10^{-34}$ J-s $1 nm = 10^{-9} m$ $R_H=2.18 \times 10^{-18}$ J$

Electron Configurations and Quantum Principles

The 2p orbitals have a principal quantum number of n = 2 and angular quantum number of l = 1. In multi-electron atoms, these orbitals have higher energy than the 2s orbital, unlike in hydrogen atoms where they have the same energy. This energy difference affects how electrons fill orbitals.

Nitrogen's ground-state electron configuration follows Hund's rule, which states that electrons occupy orbitals of equal energy individually before pairing up. This is why nitrogen has three unpaired electrons in its 2p orbitals. The correct arrangement shows the 1s and 2s orbitals filled with paired electrons, while the three 2p orbitals each contain one electron with parallel spins.

The Heisenberg Uncertainty Principle states that σₓσₚₓ ≥ ℏ/4π, meaning you can't simultaneously know a particle's exact position and momentum. This principle is fundamental to quantum mechanics and explains why electrons exist as probability clouds rather than defined particles.

🔍 The de Broglie wavelength equation $λ = h/mv$ connects an object's wave properties to its mass and velocity. Even large objects like viruses have wavelengths, though they're extremely tiny (5.0×10⁻¹⁵ m) compared to atomic bond lengths (10⁻¹⁰ m)!

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$CHEM 2031 (Quiz 9) Name Student Number This quiz has two pages. $h=6.63 \times 10^{-34}$ J-s $1 nm = 10^{-9} m$ $R_H=2.18 \times 10^{-18}$ J$

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Chemistry130 views·Updated May 29, 2026·3 pages

General Chemistry 1: Quiz 7 Review

_jxvv@_jxvv

Quantum mechanics is a fascinating branch of chemistry that helps us understand how electrons behave in atoms. This summary covers key concepts about quantum numbers, electron configurations, and quantum principles that determine the arrangement of electrons in atoms.

of 3

$CHEM 2031 (Quiz 9) Name Student Number This quiz has two pages. $h=6.63 \times 10^{-34}$ J-s $1 nm = 10^{-9} m$ $R_H=2.18 \times 10^{-18}$ J$

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Quantum Numbers and Electron Configuration Basics

💡 Think of quantum numbers as an electron's "address" in an atom - n is like the neighborhood, l is the street, ml is the house number, and ms is the specific room!

of 3

$CHEM 2031 (Quiz 9) Name Student Number This quiz has two pages. $h=6.63 \times 10^{-34}$ J-s $1 nm = 10^{-9} m$ $R_H=2.18 \times 10^{-18}$ J$

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Electron Configurations and Quantum Principles

🔍 The de Broglie wavelength equation $λ = h/mv$ connects an object's wave properties to its mass and velocity. Even large objects like viruses have wavelengths, though they're extremely tiny (5.0×10⁻¹⁵ m) compared to atomic bond lengths (10⁻¹⁰ m)!

of 3

$CHEM 2031 (Quiz 9) Name Student Number This quiz has two pages. $h=6.63 \times 10^{-34}$ J-s $1 nm = 10^{-9} m$ $R_H=2.18 \times 10^{-18}$ J$

Sign up to see the content. It's free!

Access to all documents
Improve your grades
Join milions of students